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Sergeeva-Olga [200]
2 years ago
6

Simplify the following expression. 16x^6-12x^4+2x^2 / _2x^2

Mathematics
1 answer:
mojhsa [17]2 years ago
5 0
6x^2/2x^2
.......................
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Please answer this quickly
scZoUnD [109]

Answer:

14 and 16

Step-by-step explanation:

your adding 2 to each each time, if your looking for the multiplied awnser its 224

8 0
3 years ago
6. What are the mean and the mode of the following set of data: 5, 12, 1, 5, 7
Firlakuza [10]
Mode is 5 and mean is 6:))
8 0
3 years ago
Read 2 more answers
PLZ HELP: the answer to 5(x-1) the answer to this cannot be found online. THIS IS SIMPLE MATH I'M STILL CONFUSED SO PLZ EXPLAIN
777dan777 [17]
That would be 5x-5 because the number inside is multiplied by the numbers inside due to the brackets. Hope u understand my explanation.
4 0
3 years ago
The selling price s , of an item is S equals C plus MC where C is the cost of the item and Emma is the percent markup based on c
Evgen [1.6K]

9514 1404 393

Answer:

  M = (S -C)/C

Step-by-step explanation:

Starting with ...

  S = C + MC

we want to solve for M.

  S - C = MC . . . . subtract the term not containing M

  (S -C)/C = M . . . . divide by the coefficient of M

Solved for M, the formula is ...

  M = (S -C)/C

3 0
2 years ago
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
3 years ago
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