Precipitation is the short-term condition of the atmosphere
<span>0.5035 so go with .50 moles.
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Answer:
The answer to your question is the letter C) 5648 kJ/mol
Explanation:
Data
C₁₂H₂₂O₁₁ + 12 O₂ ⇒ 12 CO₂ + 11 H₂O
H° C₁₂H₂₂O₁₁ = -2221.8 kJ/mol
H° O₂ = 0 kJ / mol
H° CO₂ = -393.5 kJ/mol
H° H₂O = -285.8 kJ/mol
Formula
ΔH° = ∑H° products - ∑H° reactants
Substitution
ΔH° = 12(-393.5) + 11(-285.8) - (-2221.8) - (0)
ΔH° = -4722 - 3143.8 + 2221.8
Result
ΔH° = -5644 kJ/mol
Answer:
includes the coefficients that are needed for balancing the equation.
Explanation:
Answer:
747mL of the 0.157mL are needed
Explanation:
To find the grams of salt we need to convert these grams to moles using molar mass of magnesium nitrate (148.3g/mol). Then, with the molar concentration we can convert the moles to liters and, as last, to milliliters, as follows:
<em>Moles Mg(NO₃)₂:</em>
17.4g * (1mol / 148.3g) = 0.117 moles of magnesium nitrate
<em>Volume:</em>
0.117 moles * (1L / 0.157moles) = 0.747L
= 747mL of the 0.157mL are needed
<em>In a 0.157M solution there are 0.157 moles per liter of solution</em>
