1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
icang [17]
3 years ago
14

Select the electron domain geometry and the molecular geometry for an ammonia molecule, NH3. Check all of the boxes that apply.

You may use the periodic table if needed.
trigonal-planar electron domain geometry
trigonal-planar molecular geometry
trigonal-pyramidal electron domain geometry
trigonal-pyramidal molecular geometry
tetrahedral electron domain geometry
tetrahedral molecular geometry
Chemistry
1 answer:
Mariulka [41]3 years ago
8 0

The correct answer is option 4 and 5.

The electron domain geometry for an ammonia molecule, NH₃ has tetrahedral electron domain geometry. In NH₃ there are three bond pair electrons and one lone pair electron. Therefore, NH₃ has four electron pairs which are distributed in a tetrahedral shape.

The molecular geometry for an ammonia molecule, NH₃ is trigonal-pyramidal molecular geometry. Ammonia has one lone pair of electron and three bond pairs of electrons thus the resulting molecular geometry is trigonal-pyramidal.  


You might be interested in
How many moles are in 5.25 L of oxygen gas as stp
Masteriza [31]

Answer:

The correct answer is 0, 235 mol

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:

1 atm x 5, 25l = n  x 0, 082 l atm / K mol x 273 K

n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K

n= 0, 235 mol

8 0
3 years ago
A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0
3 years ago
What are the complete Ionic and Net Ionic equations for the following
zhenek [66]

Answer:

Check photo

Explanation:

5 0
3 years ago
A. glycerol
Natasha2012 [34]
Bzjnu8:i9.8&9olzlns soccer
4 0
3 years ago
10) One mole of a diatomic ideal gas is initially at a temperature of 127 °C and
Vladimir79 [104]
Ok hold on one second
6 0
3 years ago
Other questions:
  • What is the molecular geometry of the underlined carbon atom in the following compound: HC-C-CH3?
    10·1 answer
  • How many miles of barium hydroxide are in 2400 grams of Ba(OH)2
    8·2 answers
  • Match the element with its description. Match Term Definition Potassium A) Has properties of both metals and nonmetals Barium B)
    14·1 answer
  • What is the consecration of a solution that is made by diluting 50.0 mL of a 40.0 M NaCl solution to a final volume of 1000.0 mL
    12·1 answer
  • Describe how to use physical properties to seperate a mixture of ice cubes and nails
    13·1 answer
  • How does adding a non-volatile solute to a pure solvent affect the freezing point of the pure solvent?
    7·1 answer
  • 2. When lithium reacts with bromine to form the compound LiBr,each lithium atom1) gains one electron and becomes a negatively ch
    8·1 answer
  • How many moles are in 5.0 x 10 *23 atoms of iron?
    11·1 answer
  • How much heat, in kJ, will be absorbed by a 25.0 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature fr
    13·1 answer
  • Describe what happens to the electrons in a neon that is heated to incandescence and then when the heat energy is removed.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!