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icang [17]
4 years ago
14

Select the electron domain geometry and the molecular geometry for an ammonia molecule, NH3. Check all of the boxes that apply.

You may use the periodic table if needed.
trigonal-planar electron domain geometry
trigonal-planar molecular geometry
trigonal-pyramidal electron domain geometry
trigonal-pyramidal molecular geometry
tetrahedral electron domain geometry
tetrahedral molecular geometry
Chemistry
1 answer:
Mariulka [41]4 years ago
8 0

The correct answer is option 4 and 5.

The electron domain geometry for an ammonia molecule, NH₃ has tetrahedral electron domain geometry. In NH₃ there are three bond pair electrons and one lone pair electron. Therefore, NH₃ has four electron pairs which are distributed in a tetrahedral shape.

The molecular geometry for an ammonia molecule, NH₃ is trigonal-pyramidal molecular geometry. Ammonia has one lone pair of electron and three bond pairs of electrons thus the resulting molecular geometry is trigonal-pyramidal.  


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Step 1: Write the unbalanced equation,

                                 C₂H₆  +  O₂    →    CO₂  +  H₂<span>O

There are 2 C at left hand side and 1 carbon at right hand side. So, multiply CO</span>₂ by 2 to balance C atoms at both side. So,

                                 C₂H₆  +  O₂    →   2 CO₂  +  H₂O

Now, count number of H atoms at both sides. There are 6 H atoms at left hand side and 2 at right hand side. Multiply H₂O by 3 to balance H atoms.


                                 C₂H₆  +  O₂    →   2 CO₂  +  3 H₂O

At last, balance O atoms. There are 2 O atoms at left hand side and 3 O atoms at right hand side. Multiply O₂ with 1.5 (i.e. 3/2) to balance O atoms. i.e.

                                 C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O

Hence, the equation is balanced. If you want to make equation fraction free then multiply all equation with 2. i.e.

                           ( C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O ) × 2

                                2 C₂H₆  +  3 O₂    →   4 CO₂  +  6 H₂O
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