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Sergeu [11.5K]
4 years ago
7

What is the total mass of Hydrogen in each of the molecules?

Chemistry
1 answer:
frutty [35]4 years ago
3 0

Explanation:

a) In 1 mole of methane there are 4 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 4 × 1 g = 4 g

b) In 1 mole of chloroform there are 1 mole of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 1× 1 g = 1 g

c) In 1 mole of C_{12}H_{10}O_{16} there are 10 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of C_{12}H_{10}O_{16} = 10 × 1 g = 10 g

d)In 1 mole of CH_3CH_2CH_2CH_2CH_3 there are 12 moles of hydrogen atom.

CH_3CH_2CH_2CH_2CH_3=C_5H_{12}

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of CH_3CH_2CH_2CH_2CH_3 = 12 × 1 g = 12 g

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Which natural occurrence is shown ? Check all that apply.
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Answer:

2. flooding

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Explanation:

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Which of the following shows a decrease in entropy?
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3 years ago
What is the mass in grams of 1.00 x 10 24 atoms of Mn?
Alex17521 [72]
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0
3 years ago
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Consider dissolving sugar in water and magnesium sulfate in water. is any new substance being produced? what happens after sodiu
Olenka [21]

Answer:

Here's what I get  

Explanation:

1. Sugar

(a) Dissolving in water

The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.

2. Magnesium sulfate

(a) Dissolving in water

The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.

8 0
3 years ago
Glycerine is known as a negative catalyst.why?​
ioda

Answer:

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Explanation:

6 0
3 years ago
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