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Sergeu [11.5K]
3 years ago
7

What is the total mass of Hydrogen in each of the molecules?

Chemistry
1 answer:
frutty [35]3 years ago
3 0

Explanation:

a) In 1 mole of methane there are 4 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 4 × 1 g = 4 g

b) In 1 mole of chloroform there are 1 mole of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 1× 1 g = 1 g

c) In 1 mole of C_{12}H_{10}O_{16} there are 10 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of C_{12}H_{10}O_{16} = 10 × 1 g = 10 g

d)In 1 mole of CH_3CH_2CH_2CH_2CH_3 there are 12 moles of hydrogen atom.

CH_3CH_2CH_2CH_2CH_3=C_5H_{12}

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of CH_3CH_2CH_2CH_2CH_3 = 12 × 1 g = 12 g

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Violet light has a wavelength of 422 nm, how much energy is found in this photon of violet light?
pashok25 [27]

Answer:

3.025eV

Explanation:

Energy of a photon is given by

E=hν

Where h is the Planck's constant

And ν represents the frequency of the photon .

Now for violet light wavelength λ=410nm= 410x10^-9m

By using the formula ν=c/λ

where c represents speed of light I.e 3 x 10^8 m/s

Calculating energy of violet photon we have

E=hc/λ

h=6.626 x 10^-34 J.s

On inserting the value in the formula , we get

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To convert it into electron volts we need to divide it by 1.602 x10^-19.

The final result what we have is E=3.026eV.

Note: the result calculated is according to the above value . result may vary according to the values taken .

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How many moles of ethanol are produced starting with 500.g glucose?
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<h3>Answer:</h3>

5.55 mol C₂H₅OH

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

[Given] 500. g C₆H₁₂O₆ (Glucose)

[Solve] moles C₂H₅OH (Ethanol)

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH

[PT] Molar mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up conversion:                                                                                 \displaystyle 500 \ g \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{180.18 \ g \ C_6H_{12}O_6})(\frac{2 \ mol \ C_2H_5OH}{1 \ mol \ C_6H_{12}O_6})
  2. [DA} Multiply/Divide [Cancel out units]:                                                         \displaystyle 5.55001 \ mol \ C_2H_5OH

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH

8 0
3 years ago
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