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navik [9.2K]
2 years ago
14

What volume will 5.6 moles of sulfur hexafluoride

Chemistry
1 answer:
vovikov84 [41]2 years ago
4 0

Answer:

19.6 L SF₆

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and simplify to find "V".

P = 9.4 atm                               R = 0.08206 atm*L/mol*K

V = ? L                                      T = 128 °C + 273.15 = 401.15 K

n = 5.6 moles

PV = nRT

(9.4 atm)V = (5.6 moles)(0.08206 atm*L/mol*K)(401.15 K)

(9.4 atm)V = 184.3429

V = 19.6 L

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Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17. g of octane is mi
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Answer: 52.8 g of CO_2

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of octane

\text{Number of moles}=\frac{17.0g}{114g/mol}=0.150moles

b) moles of oxygen

\text{Number of moles}=\frac{93.0g}{32g/mol}=2.91moles

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

According to stoichiometry :

2 moles of C_8H_{18} require 25 moles of O_2

Thus 0.150 moles of  C_8H_{18} require=\frac{25}{2}\times 0.150=1.875moles  of O_2

Thus C_8H_{18} is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

As 2 moles of C_8H_{18} give =  16 moles of CO_2

Thus 0.150 moles of C_8H_{18} give =\frac{16}{2}\times 0.150=1.2moles  of CO_2

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What is the mass defect of lithium? Assume the following:
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Answer:

Δm = 3.0684

Explanation:

Data Given:

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Solution:

Mass Defect:

Mass defect is the difference of mass number of an atom and its atomic number.

Formula used

Δm = [Z (mass of proton + mass of nutron)  + ( A − Z ) mass of nutron] − m of atom

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Δm = mass defect (amu)

Z = atomic number

A = mass number

Put values in formula

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Δm = [3 (2.016)  + (4) 1.0087 ] − 7.0144

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