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navik [9.2K]
2 years ago
14

What volume will 5.6 moles of sulfur hexafluoride

Chemistry
1 answer:
vovikov84 [41]2 years ago
4 0

Answer:

19.6 L SF₆

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and simplify to find "V".

P = 9.4 atm                               R = 0.08206 atm*L/mol*K

V = ? L                                      T = 128 °C + 273.15 = 401.15 K

n = 5.6 moles

PV = nRT

(9.4 atm)V = (5.6 moles)(0.08206 atm*L/mol*K)(401.15 K)

(9.4 atm)V = 184.3429

V = 19.6 L

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What is the type of bonding in a molecule of sulfur dioxide?​
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Answer:

Covalent bonding

Explanation:

Sulfur Dioxide is a process of covalent bonding, since Sulfur and Oxygen are both non-metals. The Sulfur is in the center surrounded by 2 Oxygen atoms.

6 0
3 years ago
What is the mole fraction of Ba(OH)2 in an aqueous solution that contains 22.8% Ba(OH)2 by mass?
antoniya [11.8K]

Answer:

0.03

Explanation:

22.8 g Ba(OH)2 (1 mol Ba (OH)2/ 171.34 g) = 0.133 mol Ba (OH)2

77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O

X= molar fraction= mol Ba(OH)2/ mol total

X= 0.133/ (0.133+4.29) = 0.03

4 0
3 years ago
How can two atoms of the same chemical element be different?
suter [353]

The answer is B as isotopes are different versions of the same chemical element containing the same amount of protons and electrons but different amounts of neutrons.

8 0
3 years ago
The Earth's circumference around the equator is slightly bulged as compared to the circumference around the poles. if the circum
Igoryamba
The earth in m is 510
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3 years ago
A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.
Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L

Therefore, the new volume of the air is, 6.83 L

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3 years ago
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