The temperature of the countertop changes by 0.032 °C
The quantity of heat transferred to the countertop is given by
Q = CΔT where Q = quantity of heat transferred to the countertop = 5000 J = 5 kJ, C = heat capacity of the countertop = 158.5 kJ/°C and ΔT = temperature change of the countertop.
Since we require the temperature change of the countertop, we make ΔT subject of the formula.
So, ΔT = Q/C
So, substituting the values of the variables into the equation, we have
ΔT = Q/C
ΔT = 5 kJ/158.5 kJ/°C
ΔT = 0.032 °C
So, the temperature of the countertop changes by 0.032 °C
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Answer:
Mass = 112.54 g
Explanation:
Given data:
Mass of copper = 18 g
How much copper(II) nitrate formed = ?
Solution:
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
Number of moles of copper:
Number of moles = mass/ molar mass
Number of moles = 18 g/ 29 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of Cu with Cu(NO₃)₂ .
Cu : Cu(NO₃)₂
1 : 1
0.6 : 0.6
Mass of Cu(NO₃)₂ :
Mass = number of moles × molar mass
Mass = 0.6 mol × 187.56 g/mol
Mass = 112.54 g
Carbohydrates
Lipids
Protein
Nucleic acids
Answer:
Number of protons = 52, Number of electrons = 52, Number of neutrons = 76
Explanation:
