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Deffense [45]
3 years ago
7

True or false? A proton carries a positive charge.

Physics
1 answer:
Setler79 [48]3 years ago
6 0
True a proton carries a positive charge, a neutron carries a neutral charge and an electron carries a negative charge.
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Explain why the focal point of a diverging lens is called a virtual focal point.
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The concave lens is a diverging lens, because it causes the light rays to bend away (diverge) from its axis. In this case, the lens has been shaped so that all light rays entering it parallel to its axis appear to originate from the same point, F, defined to be the focal point of a diverging lens.
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Physicists at CERN study the conditions present during the big bang by using machines to do what?
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Four equal masses m are so small they can be treated as points, and they are equallyspaced along a long, stiff mass less wire. T
gavmur [86]

The moment of inertia of a point mass about an arbitrary point is given by:

I = mr²

I is the moment of inertia

m is the mass

r is the distance between the arbitrary point and the point mass

The center of mass of the system is located halfway between the 2 inner masses, therefore two masses lie ℓ/2 away from the center and the outer two masses lie 3ℓ/2 away from the center.

The total moment of inertia of the system is the sum of the moments of each mass, i.e.

I = ∑mr²

The moment of inertia of each of the two inner masses is

I = m(ℓ/2)² = mℓ²/4

The moment of inertia of each of the two outer masses is

I = m(3ℓ/2)² = 9mℓ²/4

The total moment of inertia of the system is

I = 2[mℓ²/4]+2[9mℓ²/4]

I = mℓ²/2+9mℓ²/2

I = 10mℓ²/2

I = 5mℓ²

4 0
3 years ago
The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr
vichka [17]

Answer:

Drift velocity in m/s is 1.84 \times 10^{-8}\ m/s.

Explanation:

<em>Formula for Drift Velocity is</em>:

u = \dfrac{I}{nAq}

Where I is the current

n is the number of electrons in 1 m^3 or the electron density

A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = 8.49 \times 10^{28}\ electrons/m^3

I = 1 A

A = 0.40 cm^2 = 40 \times 10^{-4} m^{2}

We know that q = 1.6\times10^{-19} C

Putting all the values to find drift velocity:

u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s

So, <em>drift velocity in m/s</em> is 1.84 \times 10^{-8}\ m/s.

3 0
3 years ago
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