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Deffense [45]
3 years ago
7

True or false? A proton carries a positive charge.

Physics
1 answer:
Setler79 [48]3 years ago
6 0
True a proton carries a positive charge, a neutron carries a neutral charge and an electron carries a negative charge.
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The acacia ant is a parasite on the acacia tree. True False
stiv31 [10]
<em>The answer you are looking for is: </em>
<em><u>True </u></em>
<em>Hope that helps!! </em>
<em>Have a wonderful day!!</em>
4 0
3 years ago
What influence do culture and customs have on beliefs about mental disorders? Customs really don't determine what is considered
Mumz [18]

Answer:

The culture of the patient, also known as the consumer of mental health services, influences many aspects of mental health, mental illness, and patterns of health care utilization. One important cautionary note, however, is that general statements about cultural characteristics of a given group may invite stereotyping of individuals based on their appearance or affiliation. Because there is usually more diversity within a population than there is between populations (e.g., in terms of level of acculturation, age, income, health status, and social class), information in the following sections should not be treated as stereotypes to be broadly applied to any individual member of a racial, ethnic, or cultural group.

Explanation:

4 0
3 years ago
A 0.10 kg meter stick is held perpendicular to a vertical wall by a 2.5 mm string going from the wall to the far end of the stic
il63 [147K]

Explanation:

a)

Sum of moments = 0 (Equilibrium)

T . cos (Q)*L = m*g*L/2

cos Q = \frac{\sqrt{(2.5^2 - L^2) } }{2.5}

T*\frac{\sqrt{(2.5^2 - L^2) } }{2.5} * L = 0.1 *9.81*L/2

T = \frac{2.4525}{\sqrt{(2.5)^2 - L^2} }

b) If the String is shorter the Q increases; hence, Cos Q decreases which in turn increases Tension in the string due to inverse relationship!

c)

T = \frac{1.962}{\sqrt{(2)^2 - L^2} }

6 0
3 years ago
A pendulum is used in a large clock. The pendulum has a mass of 2 kg. If the pendulum is moving at a speed of 2.9 m/s when it re
Rufina [12.5K]
This is a classic example of conservation of energy. Assuming that there are no losses due to friction with air we'll proceed by saying that the total energy mus be conserved.
E_m=E_k+E_p
Now having information on the speed at the lowest point we can say that the energy of the system at this point is purely kinetic:
E_m=Ek=\frac{1}{2}mv^2
Where m is the mass of the pendulum. Because of conservation of energy, the total energy at maximum height won't change, but at this point the energy will be purely potential energy instead.
E_m=E_p
This is the part where we exploit the Energy's conservation, I'm really insisting on this fact right here but it's very very important, The totam energy Em was
E_M=\frac{1}{2}mv^2
It hasn't changed! So inserting this into the equation relating the total energy at the highest point we'll have:
E_p=mgh=E_m=\frac{1}{2}mv^2
Solving for h gives us:
h=\frac{v^2}{2g}.
It doesn't depend on mass!

4 0
3 years ago
Read 2 more answers
The lighting needs of a storage room are being met by six fluorescent light fixtures, each fixture containing four lamps rated a
Amanda [17]

Answer:

amount of energy  = 4730.4 kWh/yr

amount of money = 520.34 per year

payback period = 0.188 year

Explanation:

given data

light fixtures = 6

lamp = 4

power = 60 W

average use = 3 h a day

price of electricity = $0.11/kWh

to find out

the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66

solution

we find energy saving by difference in time the light were

ΔE = no of fixture × number of lamp × power of each lamp × Δt

ΔE is amount of energy save and Δt is time difference

so

ΔE = 6 × 4 × 365 ( 12 - 9 )

ΔE = 4730.4 kWh/yr

and

money saving find out by energy saving and unit cost that i s

ΔM = ΔE × Munit

ΔM = 4730.4 × 0.11

ΔM = 520.34 per year

and

payback period is calculate as

payback period = \frac{excess initial cost}{\Delta M}

payback period = \frac{32 + 66}{520.34}

payback period = 0.188 year

8 0
4 years ago
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