Question

Two containers are at the same temperature. The first

Answer 1

Answer:

From Maxwell-Boltzmann distribution of molecules and their speeds,

average speed, Vavg = √($\frac{8RT}{πM}$)

and Root mean speed, Vrms = √($\frac{3RT}{M}$)

Given Vavg2 = 5Vrms1

Vavg2 = √($\frac{8RT}{πM2}$) ................ eqn 1

Vrms1 = √($\frac{3RT}{M1}$) --------------eqn 2

To find m1/m2, we divide eqn 1 by eqn 2,

we have, Vavg2/Vrms1 = √($\frac{8m1}{3πm2}$)

since Vavg2 = 5Vrms1, it becomes, 5 = √($\frac{8m1}{3πm2}$)

Therfore, m1/m2 = 25 * 3π/8 = 29.45

the mass ratio m1/m2 = 29.45.