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Readme [11.4K]
2 years ago
12

A given substance is a white, granular solid at 25 °C that does not conduct electricity. It melts at 750 °C wand the melt conduc

ts electricity. It dissolves easily in water and produces a conductive solution. Identify the type of crystal and justify your answer.
Chemistry
1 answer:
xxMikexx [17]2 years ago
3 0

Answer:

Ionic crystal

Explanation:

An ionic crystal has a high melting point. In an ionic crystal, the ions are tightly held in electrostatic attraction by their oppositely charged neighbors forming a rigid three dimensional lattice. However, when this solid melts, the rigid crystal structure collapses and the individual ions become free and mobile. Hence the melt conducts electricity.

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The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume
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Answer:

0.83 mL

Explanation:

Given data

  • Initial concentration (C₁): 12 M
  • Initial volume (V₁): ?
  • Final concentration (C₂): 1.0 M
  • Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0
3 years ago
Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the
lions [1.4K]

<u>Answer:</u> The concentration of solute is 0.503 mol/L

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=icRT

where,

\pi = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = 0.08\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L

Hence, the concentration of solute is 0.503 mol/L

5 0
3 years ago
Is warm water or cold water more dense
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Cold water is denser
8 0
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A gas mixture contains SO 2 SO2 ( molar mass = 64 g/mol ) (molar mass=64 g/mol) and no other source of sulfur. If the mixture is
Slav-nsk [51]

Answer : The percentage (by mass) of SO_2 in the mixture is 20 %

Explanation :

As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.

Mass of sulfur = 10 g

Mass of mixture = 100 g

Now we have to calculate the mass of SO_2.

As, 32 grams of sulfur present in 64 grams of SO_2

So, 10 grams of sulfur present in \frac{10}{32}\times 64=20 grams of SO_2

Thus, the mass of SO_2 is 20 grams.

Now we have to calculate the percentage (by mass) of SO_2 in the mixture.

\% \text{ of }SO_2=\frac{\text{Mass of }SO_2}{\text{Mass of mixture}}\times 100

\% \text{ of }SO_2=\frac{20g}{100g}\times 100=20\%

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Which contributes to the polarity of a water molecule?
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Answer:

B

Explanation:

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