Answer:
0.83 mL
Explanation:
Given data
- Initial concentration (C₁): 12 M
- Final concentration (C₂): 1.0 M
- Final volume (V₂): 10.0 mL
We can calculate the initial volume of HCl using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.0 M × 10.0 mL / 12 M
V₁ = 0.83 mL
The required volume of the initial solution is 0.83 mL.
<u>Answer:</u> The concentration of solute is 0.503 mol/L
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

where,
= osmotic pressure of the solution = 24 atm
i = Van't hoff factor = 2 (for NaCl)
c = concentration of solute = ?
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:

Hence, the concentration of solute is 0.503 mol/L
Answer : The percentage (by mass) of
in the mixture is 20 %
Explanation :
As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.
Mass of sulfur = 10 g
Mass of mixture = 100 g
Now we have to calculate the mass of
.
As, 32 grams of sulfur present in 64 grams of 
So, 10 grams of sulfur present in
grams of 
Thus, the mass of
is 20 grams.
Now we have to calculate the percentage (by mass) of
in the mixture.


Therefore, the percentage (by mass) of
in the mixture is 20 %