The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
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The answer is was he number is being divided by 10
The anser is 20 that what i think
<u>Answer:</u>
y = 5x (x+2)
<u>Step-by-step explanation:</u>
We are given the following the quadratic function and we are to rewrite it in intercept or factored form:
We can factorize the given expression so taking the common factors out of it to get:
Therefore, the factored form of the given quadratic function is y = 5x (x+2).
Answer:
y=1/2x
Step-by-step explanation:
math is math
