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3 years ago

How do you find the volume of a lead ball if the mass is 454 grams?

Physics

1 answer:

inna [77]3 years ago

4 0

By doing this in your calculator: 4/3 times <span>π and 454 to the third power. good luck :)</span>

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Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?

Xelga [282]

<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

30 cm = 0.3 m (distance)

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

$\small \boxed{work \: done \: by \: Ryan \: = 3 \: Joules}$

4 0

2 years ago

If the velocity is 50 and the time is 5 seconds what is the acceleration?

disa [49]

Just divide the both, you will get the answer!

does it sound rude?

im sorry for that!

3 0

2 years ago

Indicate on the chart whether you would classify each model as representing an element, compound, or mixture.

Ne4ueva [31]

Answer:

1 compound

2 mixture

3 elements

4 0

3 years ago

Read 2 more answers

Which applied force will allow a 7.65 kg block of ice to begin sliding on a sheet of ice? The block of ice has a kinetic coeffic

Anni [7]

Answer:

force for start moving is 7.49 N

force for moving constant velocity 2.25 N

Explanation:

given data

mass = 7.65 kg

kinetic coefficient of friction = 0.030

static coefficient of friction = 0.10

solution

we get here first weight of block of ice that is

weight of block of ice = mass × g

weight of block of ice = 7.65 × 9.8 = 74.97 N

so here Ff = Fa

so for force for start moving is

Fa = weight × static coefficient of friction

Fa = 74.97 × 0.10

Fa = 7.49 N

and

force for moving constant velocity is

Fa = weight × kinetic coefficient of friction

Fa = 74.97 × 0.030

Fa = 2.25 N

7 0

3 years ago

Read 2 more answers

If you hold a bar magnet in each hand and bring your hands together, will the force be attractive or repulsive if the magnets ar

Law Incorporation [45]

a) The force is repulsive

b) The force is attractive

Explanation:

Every magnet has a magnetic field around it. It is possible to distinguish two different poles in the magnet, according to the direction of the magnetic field: in particular, the lines of the field go out from the North pole and go into the South Pole. When a magnet is broken, two new magnets are formed, each of them having its own north and south pole.

The force between two magnets can be either attractive or repulsive, depending on which poles are facing each other. We have the following situation:

The magnetic force between two like poles (north-north and south-south) is repulsive
The magnetic force between two opposite poles (north-south) is attractive

Therefore, we have the following situations in this problem:

Here we are holding the two north poles together: since they are like poles, they repel each other, so the force in this case is repulsive

Here we are holding a north pole and a south pole together: since they are opposite poles, they attract each other, so the force in this case is attractive

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

5 0

3 years ago