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kumpel [21]
1 year ago
13

A 10-liter container has 2 moles of oxygen at a pressure of 92 kpa. The effective speed (rms) of the oxygen molecules in the gas

is?
Chemistry
1 answer:
bezimeni [28]1 year ago
4 0

The effective speed (rms) of the oxygen gas is 293.68 m/s.

<h3></h3><h3>What is Root-mean-square velocity?</h3>

Root mean square velocity is the square root of the mean of squares of the velocity of individual gas molecules

v_{rms}=\sqrt[]{\frac{3RT}{M} }

<em>where </em>R = universal gas constant

M = molar mass of the gas in kg/mol

T = temperature in Kelvin

According to the ideal gas law,

PV = nRT

RT = \frac{PV}{n}

Substitute in the rms velocity formula,

v_{rms} = \sqrt[]{\frac{3PV}{nM} }

P = 92 kPa, V = 10 L, n = 2 moles and M = 32 x 10⁻³ kg/mol

v_{rms} = \sqrt[]{\frac{3\times92\times10}{2\times32\times10^-^3} }

=293.68 m/s

Thus, the effective speed (rms) of O₂ gas is 293.68 m/s.

Learn more about Root-mean-square velocity:

brainly.com/question/15995507

#SPJ4

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Answer:

7 mol

Explanation:

Caffeine molecular formula C8H10N4O2. It has 2 atoms of oxygen.

                          C8H10N4O2         - 2O

                           1 mol                        2 mol

                           3.5 mol                    x mol

x = 3.5*2/1 = 7 mol

3 0
3 years ago
Combine each side and then balance the whole equation. Al+HCl=AlCl3+H^+
Aneli [31]

Answer:

2Al + 6 HCl ---> 2AlCl_3 + 3 H_2

Explanation:

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we will first write the half reactions

Half oxidation reaction

Al -----> Al^{3+} + 3^{e-}\\2H^+ 2e^- ----> H_2\\Cl + e^- -----> Cl^-

Now will write the complete equation-

Al + HCl -----> AlCl_3 + H_2

The balanced equation would be

2Al + 6 HCl ---> 2AlCl_3 + 3 H_2

5 0
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What group would this element be in?
Lesechka [4]
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4 0
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onsider the reversible dissolution of lead(II) chloride. P b C l 2 ( s ) − ⇀ ↽ − P b 2 + ( a q ) + 2 C l − ( a q ) PbClX2(s)↽−−⇀
Sveta_85 [38]

Answer:

9.34x10^-4

Explanation:

Step 1:

The balanced equation for the reaction.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

Step 2:

Data obtained from the question:

Mass of PbCl2 = 0.2393 g

Volume = 50mL

concentration of Pb^2+, [Pb^2+] = 0.0159 M

Concentration of Cl^-, [Cl^-] = 0.0318 M

Equilibrium constant, Kc =?

Step 3:

Determination of the number of mole PbCl2.

The number of mole of PbCl2 can be obtained as follow:

Molar Mass of PbCl2 = 207 + (35.5x2) = 278g/mol

Mass of PbCl2 = 0.2393 g

Number of mole =Mass /Molar Mass

Number of mole of PbCl2 = 0.2393/278 = 8.61x10^-4 mole

Step 4:

Determination of Molarity of PbCl2.

At this stage we shall obtain the molarity of PbCl2. This is shown below:

Mole of PbCl2 = 8.61x10^-4 mole

Volume = 50mL = 50/1000 = 0.05L

Molarity of PbCl2 =?

Molarity = mole /Volume

Molarity of PbCl2 = 8.61x10^-4/0.05

Molarity of PbCl2 = 0.01722 M

Step 5:

Determination of the equilibrium constant Kc.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

The equilibrium constant Kc for the equation above is given by:

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

[Pb^2+] = 0.0159 M

[Cl^-] = 0.0318 M

[PbCl2] = 0.01722 M

Kc =?

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

Kc = 0.0159 x (0.0318)^2/ 0.01722

Kc = 9.34x10^-4

5 0
3 years ago
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