1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
motikmotik
3 years ago
12

How many moles of aluminum are in this aluminum can? Answer: ____________ (25 pts) Calculate the number of aluminum atoms in thi

s can. Answer: _______________ (25 pts) The Amount of Aluminum is 12.69g
Chemistry
1 answer:
Sonja [21]3 years ago
5 0

Answer:a)No of moles of Aluminium=0.4703

b)number of aluminum atoms=2.832 x 10^23 atoms

Explanation:

a)Given that The Amount/ Mass of Aluminum is 12.69g

We know that

No of moles =Mass/ Molar mass

Molar mass of Aluminium, Al is 26.982 g/mol

No of moles =12.69g/26.982 g/mol

No of moles =0.4703

Also

b) 1  mole of aluminium must contain  6.022  x 10^23  atoms of aluminium  

which is  known as Avogadro's constant.

Therefore, 0.4703 moles will contain 0.4703 x  6.022  x 10^23  atoms =2.832 x 10^23 atoms

You might be interested in
How many milliliters of ammonium sulfate solution having a concentration of 0.218 M are needed to react completely with 62.6 ml
BartSMP [9]

Answer:

330 mL of (NH₄)₂SO₄ are needed

Explanation:

First of all, we determine the reaction:

(NH₄)₂SO₄  +  2NaOH →  2NH₃  +  2H₂O  +  Na₂SO₄

We determine the moles of base:

(First, we convert the volume from mL to L) → 62.6 mL . 1L/1000 mL = 0.0626L

Molarity . volume (L) = 2.31 mol/L . 0.0626 L = 0.144 moles

Ratio is 2:1. Therefore we make a rule of three:

2 moles of hydroxide react with 1 mol of sulfate

Then, 0.144 moles of NaOH must react with (0.144 .1) /2 = 0.072 moles

If we want to determine the volume → Moles / Molarity

0.072 mol / 0.218 mol/L = 0.330 L

We convert from L to mL → 0.330L . 1000 mL/1L = 330 mL

6 0
3 years ago
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
3 years ago
Why are there 2 bonds holding the oxygen atoms together?​
tino4ka555 [31]

Answer:

Because Oxygen shares 2 electrons with mutual bond interaction forming covalent bond . thus it is diatomic due to K shell 2 electrons mutual sharing .

Explanation:

8 0
3 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
Please help me:( I’ll give u points of its right
goldenfox [79]

Answer:

k

p

p

k

k

I believe.. ............

8 0
3 years ago
Other questions:
  • Why is calgon conditioning better than phosphate conditioning?
    6·1 answer
  • How are biotic factors different from abiotic factors?
    14·1 answer
  • A mixture of gases with a pressure of 800 mmhg contains 10% oxygen and 90% nitrogen by volume. what is the partial pressure of t
    13·2 answers
  • What are the reactants of photosynthesis?carbon dioxide and hydrogenhydrogen, oxygen, and waterlight energy, water, and carbon d
    8·2 answers
  • Chromium crystallizes with a body-centered cubic unit cell. The radius of a chromium atom is 125 pm . Calculate the density of s
    14·1 answer
  • Which scientist provided a foundation for john daltons work on the atomic structure
    12·1 answer
  • A balloon at sea level on earth (1 atm pressure, 19°C) takes up 14.5 L of space. The balloon travels to Mars where atmospheric p
    14·1 answer
  • Help! help! plz give 4 different between orbit and orbital​
    5·1 answer
  • What is the volume in liters that is needed to create a 2.3 M solution with 3.7 moles of Fe(OH)2? Round your answer to 1 decimal
    5·1 answer
  • 3. You are a water molecule in the ocean and are getting ready to move through the water cycle. Please describe your journey thr
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!