In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with $PBr_{3}$
In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
Full reaction scheme has been shown below

3 0

3 years ago

Carbon, hydrogen, and oxygen are always found in what type of molecule?

Snowcat [4.5K]

Carbohydrates, proteins, lipids, and Nucleic Acids.

3 0

3 years ago

How can you make an unsaturated solution from a saturated solution?

riadik2000 [5.3K]

Answer:

By heating the solution a saturated solution can be changed into an unsaturated solution. Without adding any solvent it can be changed into an unsaturated solution. Example: on heating a saturated solution of sugar in high temperature, it starts dissolving.

4 0

2 years ago

What is the pH of a 2.10 x 10⁻⁶ M solution of HCl?<br>

Delvig [45]

Answer:

pH = 5.7

Explanation:

pH = -log[H^+]

For HCl pH = -log[HCl] = - log [2.10 x 10⁻⁶ ] = 5.7

5 0

3 years ago