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Serhud [2]
3 years ago
8

One way to increase friction is to use (A.wax,B.sand,C.water ,D.oil

Physics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

using sand

Explanation:

We can increase friction by making rough surface.

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the temperature of a 2.0-kg increases by 5*c when 2,000 J of thermal energy are added to the block. What is the specific heat of
nata0808 [166]
To calculate the specific heat capacity of an object or substance, we can use the formula

c = E / m△T

Where
c as the specific heat capacity,
E as the energy applied (assume no heat loss to surroundings),
m as mass and
△T as the energy change.

Now just substitute the numbers given into the equation.

c = 2000 / 2 x 5
c = 2000/ 10
c = 200

Therefore we can conclude that the specific heat capacity of the block is 200 Jkg^-1°C^-1
3 0
3 years ago
Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before h
ASHA 777 [7]
If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres
6 0
3 years ago
If a proton is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the proton w
pantera1 [17]
Positive positive side naturally because protons always move to positive side and electron always move to negative side
3 0
3 years ago
Raindrops acquire an electric charge as they fall. Suppose a 2.4-mm-diameter drop has a charge of +18 pC, fairly typical values.
muminat

To solve this problem we will apply the concepts related to the potential, defined from the Coulomb laws for which it is defined as the product between the Coulomb constant and the load, over the distance that separates the two objects. Mathematically this is

V = \frac{kq}{r}

k = Coulomb's constant

q = Charge

r = Distance between them

q = 18 pC \rightarrow q = 1.8*10^-11 C

d = 2.4mm \rightarrow r = 1.2 mm = 1.2*10^-3 m

Replacing,

V = \frac{kq}{r}

V = \frac{ (9*10^9)*(1.8*10^{-11})}{(1.2*10^{-3})}

V = 135 V

Therefore the potential at the surface of the raindrop is 135 V

3 0
3 years ago
In the table below,which statement would best fill the missing box under isolated systems?
Nostrana [21]

Answer:

b-energy is not exchanged

Explanation:

An isolated system is a thermodynamic system in which neither energy nor matter is exchanged with the surroundings.

As such the best statement that will fill the box under an isolated system is that energy is not exchanged.

  • In an open system, both matter and energy are exchanged with the surrounding.
  • A closed system is one in which energy transfer is permissible but matter is not exchanged.
  • Energy cannot be created nor destroyed in any system. They are simply transformed.
3 0
3 years ago
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