Answer:
The net torque is 0.4962 N m
Explanation:
please look at the solution in the attached Word file
Answer:
3.6 × 10⁵ N/C = 360 kN/C
Explanation:
Let R = 2.0 cm be the radius of the sphere and q = -8.0 nC be the charge in it. Let q₁ be the charge at radius r = 1.0 cm. Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πr³
q₁ = q(r/R)³. The electric field due to q₁ at r is E₁ = kq₁/r² = kq(r/R)³/r² = kqr/R³
The electric field due to the point charge q₂ = 5.0 nC is E₂ = kq₂/r².
So, the magnitude of the total electric field at r = 1.0 cm is
E = E₁ + E₂ = kqr/R³ + kq₂/r² = k(qr/R³ + q₂/r²)
E = 9 × 10⁹(-8 × 10⁻⁹ C × 1 × 10⁻² m/(2 × 10⁻² m)³ + 5 × 10⁻⁹ C/(1 × 10⁻² m)²)
E = 9 × 10⁹(-1 × 10⁻⁵ + 5 × 10⁻⁵)
E = 9 × 10⁹(4 × 10⁻⁵)
E = 36 × 10⁴ N/C = 3.6 × 10⁵ N/C = 360 kN/C
Answer:
12.46 joules
Explanation:
The formula of potential energy is:
where m is mass, g is gravitational force (9.8 m/s^2) and h is height.
- Mass is given to be 2.3 grams.
- Gravitational Force is defined as 9.8 m/s^2.
- Height is given as 553 meters.
However, mass must be in kilograms (kg) unit so we will be converting the gram to kilogram:
We know that a gram equals to 0.001 kg so 2.3 grams will equal to 2.3 * 0.001 = 0.0023 kg.
Therefore, substitute known information in the formula of potential energy:
Therefore, the potential energy is 12.46 joules.
Answer:
29.4J
Explanation:
gravitational potential energy=mgh
mass is 15
g=9.8
h=2m
15*9.8*2=29.4
