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WITCHER [35]
2 years ago
14

Two condition required for work done​

Physics
1 answer:
mixas84 [53]2 years ago
5 0
1) There must be a force
2) There must be displacement
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In some circumstances,science will answer questions about what is good and what is evil true or false?
bagirrra123 [75]
Your answer is false since science is a subject not a religion
4 0
3 years ago
) each plate of a parallel-plate air-filled capacitor has an area of 0.0020 , and the separation of the plates is an electric fi
Dvinal [7]
I attached the full question.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
\sigma=\varepsilon_0 \frac{V}{d}
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
V=Ed
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
\sigma=\varepsilon_0 \frac{Ed}{d}=\varepsilon_0E\\
\sigma= 8.85\cdot10^{-12}\cdot 2.1\cdot 10^6= 0.0000185\frac{c}{m^2}
Please note that elecric permittivity of air is very close to  elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.

6 0
4 years ago
A satellite of mass m is moving in a circular orbit around the earth at a constant speed v and at an altitude h above the earth'
qwelly [4]

The satellite executes a rotation motion around the earth, because Earth's force of attraction plays the role of centripetal force:

Fa=Fcp=>k*Mp*m/(Rp+r)²=mv²/(Rp+r)=>v=√(k*Mp/(Rp+r))=√(6.67*10⁻¹¹*5.98*10²⁴/(6371*10³+1000*10³))=√(39.88*10¹³/(7371*10³))=√(5.41*10⁷)=7355.53 m/s


Check the calculations again !


7 0
3 years ago
The ratio of output power to input power, in percent, is called
kow [346]

That ratio is called"efficiency".  It doesn't need to be a percent. 
It can just as well be a fraction or a decimal number.

3 0
3 years ago
1) A train accelerates from 36 km/hr to 54 km/hr in 10<br> s. Find acceleration?
Crank

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

3 0
3 years ago
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