Ask question

Ask question

All categories

2 years ago

14

Two condition required for work done

1 answer:

mixas84 [53]2 years ago

5 0

1) There must be a force
2) There must be displacement

You might be interested in

2. Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is th

Gre4nikov [31]

Answer:

The magnitude of magnetic field at given point = $5.33$ × $10^{-5}$ T

Explanation:

Given :

Current passing through both wires = 5.0 A

Separation between both wires = 8.0 cm

We have to find magnetic field at a point which is 5 cm from any of wires.

From biot savert law,

We know the magnetic field due to long parallel wires.

⇒ $B = \frac{\mu_{0}i }{2\pi R}$

Where $B =$ magnetic field due to long wires, $\mu_{0} =$ $4\pi \times10^{-7}$ , $R =$ perpendicular distance from wire to given point

From any one wire $R_{1} =$ 5 cm, $R_{2} =$ 3 cm

so we write,

∴ $B = B_{1} + B_{2}$

$B = \frac{\mu_{0} i}{2\pi R_{1} } + \frac{\mu_{0} i}{2\pi R_{2} }$

$B =\frac{ 4\pi \times10^{-7} \times5}{2\pi } [\frac{1}{0.03} + \frac{1}{0.05} ]$

$B = 5.33\times10^{-5} T$

Therefore, the magnitude of magnetic field at given point = $5.33\times10^{-5} T$

3 0

3 years ago

15 POINTS PLEASE HELP! NO GUESSING

torisob [31]

He answer is A. <span>encourage agricultural usage in the watershed

if you want to read it for yourself go to
www.nature.org/ourinitiatives/regions/northamerica/unitedstates/indiana/journeywithnature/watersheds...

hope this helps you!!</span>

7 0

3 years ago

Read 2 more answers

A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the

Bond [772]

Momentum of the car is 46.2 kgm/s

8 0

3 years ago

Write any two different between work and power?

attashe74 [19]

Answer:

1. Work Is a type of Physical Activity

2. Power is Basically Having control of Society

Explanation:

3 0

3 years ago

Read 2 more answers

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i

svet-max [94.6K]

Answer:

$0.261\ \text{m}$

Explanation:

$\Delta f$ = Change in frequency = 2.1 Hz

$f$ = Frequency of source of sound = 440 Hz

$v_m$ = Maximum of the microphone

$v$ = Speed of sound = 343 m/s

$T$ = Time period = 2 s

We have the relation

$\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}$

Amplitude is given by

$A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}$

The amplitude of the simple harmonic motion is $0.261\ \text{m}$ .

4 0

2 years ago