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2 years ago

10

The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota

ted by 90 degrees. Only one of two waves is shown at a time when placing wave in standard wave format.

1 answer:

german2 years ago

4 0

Answer:

Transverse wave and Longitudinal wave and Electromagnetic wave

Explanation:

An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
Most electromagnetic waves are transverse in nature.

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A sound has 13 crests and 15 troughs in 3 seconds. When the second crest is produced the first is 2cm away from the source? Calc

Yuki888 [10]

Answer:

The wavelength will be 4 cm, frequency will be 4.66 Hz and wave speed is 18.6 cm/sec

Explanation:

Given:

No. of crest = 13

No. of trough = 15

Time = 3 seconds

Hence, 1 crest or 1 trough = $\frac{1}{2}\lambda$

therefore,

13 C + 15 T = $28(\frac{1}{2}\lambda)$

= $14\lambda$

Time given 3 seconds

= $\frac{3}{14}s$

$\nu= \frac{14}{3}$

$\nu= 4.6 Hz \approx 5 Hz$

2 cm distance is travelled is time period

$\lambda = 4 cm$

Again wave will travel in 1 T = 4 cm

wave speed v = $\lambda\times\nu$

= $4\times\frac{14}{3}$

= 18.6 cm/s

5 0

3 years ago

A mass m neutron has elastic collision with a mass m'

hoa [83]

Answer:

The neutron loses all of its kinetic energy to nucleus.

Explanation:

Given:

Mass of neutron is 'm' and mass of nucleus is 'm'.

The type of collision is elastic collision.

In elastic collision, there is no loss in kinetic energy of the system. So, total kinetic energy is conserved. Also, the total momentum of the system is conserved.

Here, the nucleus is still. So, its initial kinetic energy is 0. So, the total initial kinetic energy will be equal to kinetic energy of the neutron only.

Now, final kinetic energy of the system will be equal to the initial kinetic energy.

Now, as the nucleus was at rest initially, so the final kinetic energy of the nucleus will be equal to the initial kinetic energy of the neutron.

Thus, all the kinetic energy of the neutron will be transferred to the nucleus and the neutron will come to rest after collision.

Therefore, the neutron loses all of its kinetic energy to nucleus.

5 0

3 years ago

SI UNIT OF GRAVITY is the

pickupchik [31]

Answer:

G

Explanation:

4 0

2 years ago

A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.6 A runs through the wire

lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F $_{mg}^>$ | = I( $B^>$ × $L^>$ )

given that

I = 2.6 A

$B^>$ = 0.17

$L^>$ = 0.52

so we substitute

|F $_{mg}^>$ | = 2.6( 0.17i" × 0.52j" )

|F $_{mg}^>$ | = 0.2298 N

Therefore, the magnitude of the magnetic force on the wire is 0.2298 N

4 0

2 years ago

Professional Application. A 96 kg football player catches a 0.900 kg ball with his feet off the ground with both of them moving

Zarrin [17]

To solve this problem it is necessary to apply the equations related to the conservation of momentum.

This definition can be expressed as

$m_1u_1+m_2u_2 = (m_1+m_2)V_f$

Where

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial Velocity of each object

$V_f$ = Final velocity

Rearranging the equation to find the final velocity we have,

$V_f = \frac{m_1u_1+m_2u_2}{(m_1+m_2)}$

Our values are given as

$m_1 = 96Kg\\m_2 = 0.9Kg\\u_1 = 6.3m/s\\u_2 = 27.4m/s$

Replacing we have,

$V_f = \frac{(96)(6.3)+(0.9)(27.4)}{(96+0.9)}$

$V_f = 6.4959m/s$

Therefore the final velocity is 6.5m/s

3 0

3 years ago