Answer:
most likely 0m/s bc it was dropped, so it had to be still before
Explanation:
Answer:
B is excellent answer..............
The electric power used by the car battery is given by
where
V is the voltage of the battety
I is the current
P is the electric power.
For the battery in our problem, the voltage is V=12.0 V while the current intensity is I=0.5 A, so the power used by the battery is
Answer:
Explanation:
In equilibrium , weight of mug is equal to restoring force .
mg = kx where m is mass of mug , k is spring constant and x is extension .
k / m = g / x = 9.8 ms⁻² / .025 m
= 392
frequency of oscillation n =
= 4.46 per second.