Question

6.53 g of hydrochloric acid dissolved in 1.00 x 102 L of water

Answer 1

Answer:

$M = 9.7\times 10^{-4}\,M$

Explanation:

By reading the statement, it is inferred that molarity must be computed. The amount of moles of hydrocloric acid is:

$n = \frac{6.53\,g}{36.46\,\frac{g}{mol} }$

$n = 0.097\,moles$

Finally, the molarity of the solution is:

$M = \frac{0.097\,moles}{1\times 10^{2}\,L}$

$M = 9.7\times 10^{-4}\,M$