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3 years ago

Structural formula of 1 methyl butane

Chemistry

1 answer:

Kitty [74]3 years ago

5 0

Answer:

CH(CH3)2C2H5 or C5H12

Explanation:

Methyl butane or isopentane is an hydrocarbon or an alkane hydrocarbon with the formula C5H12. It has five carbons and twelve hydrogens. It is volatile and highly flammable. It has high boiling point and it can boil away at room temperature on a noon day. It is use as refrigerants. It can easily vanishes to the atmosphere when exposed

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3 years ago

Sterling silver contains silver and copper metals. if a sterling silver chain contains 17.6g of silver and 2.40g of copper, what

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Answer:- 0.88

Solution:- Masses of silver and copper metals are given and we are asked to calculate the percentage of silver in the alloy.

mass percent of Ag = $(\frac{mass of Ag}{mass of alloy})*100$

Mass of Ag = 17.6 g

mass of Cu = 2.40 g

mass of alloy = 17.6 g + 2.40 g = 20.0 g

Let's plug in the values in the formula:

mass percentage of Ag = $(\frac{17.6}{20.0})*100$

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3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

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3 years ago

Read 2 more answers

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3 years ago

When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the

Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

$\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}$

For 1000 C, W = x grams

$\tt x=\dfrac{1000.e}{96500}=0.0104e$

For 5x grams :

$\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C$

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3 years ago

Structural formula of 1 methyl butane​

Structural formula of 1 methyl butane