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Alecsey [184]
3 years ago
9

Draw the structures of all possible isomers for the following complexes. Indicate which isomers are enantiomer pairs. (a) Bromoc

hloro(ethylenediamine)platinum(II) (square-planar) (b) Tetra-amminedichloroiron(III) ion (octahedral) (c) Amminechlorobis(ethylenediamine)iron(III) ion (octahedral)
Chemistry
1 answer:
andriy [413]3 years ago
7 0

Answer:

structures B and C are: enantiomer pair.

Explanation:

Attached below are the structures of all possible Isomers

structures B and C  under solution 3 are enantiomer pair. <em>this is because they posses the same connectivity but exhibit opposite three dimensional shapes .</em>

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How many milliliters of a 0.211 M HI solution are needed to reduce 24.0 mL of a 0.354 M KMnO4 solution according to the followin
Novay_Z [31]

Answer:

The answer to your question is 242 ml

Explanation:

Data

HI 0.211 M   Volume = x

KMnO₄ 0.354 M   Volume = 24 ml

Balanced Chemical reaction

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Process

1.- Calculate the moles of KMnO₄  0.354 M in 24 ml

Molarity = moles / volume (L)

moles = Molarity x volume (L)

moles = 0.354 x 0.024

moles = 0.0085

2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,

              12 moles of HI --------------- 2 moles of KMnO₄

                x                     --------------- 0.0085 moles of KMnO₄

             x = (0.0085 x 12)/2

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Volume = 0.051/0.211

Volume = 0.242 L or Volume = 242 ml

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Help Recycling

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Which action would speed up a chemical reaction in aqueous solution?
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Adding more powdered reactants
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