Si el calor fuese un fluido no se agotaría, solamente cambiaría su forma o localización.
<h3>¿Qué ocurre cuando dos objetos con diferente temperatura están en contacto?</h3>
Cuando dos objetos de diferente temperatura están en contacto el calor fluye del objeto con mayor temperatura o más caliente, al objeto con menor temperatura o más frío. Esto ocurre hasta que ambos objetos alcanzan la misma temperatura.
<h3>¿Qué sucede con el calor?</h3>
El calor o energía termina se disipa hacia el entorno o la atmosfera cuando un cuerpo se enfría o hacia otro cuerpo si hay transferencia de calor, sin embargo, el calor no desaparece debido a la ley de la conservación de la energía y materia.
<h3>¿Qué sucedería si el calor fuera un fluido?</h3>
Si el calor fuera un fluido este fluido no desaparecería ni se agotaría, solamente se podría disipar a la atmósfera o ambiente.
Aprenda más sobre calor en: brainly.com/question/15890992
Answer:
P + Q2+ -> no reaction
R + P2+ -> R2+ + P
Q + S2+ -> Q2+ + S
S + P2+ -> S2+ + P
S + R2+ -> S2+ + R
S + Q2+ -> no reaction
What is the correct order of reactivity of the metals?
Most -----------------------> least
A. P R S Q
B. Q R S P
C. Q S R P
D. S Q P Rhhgu
The energy required to separate a mole of an ionic solid into gaseous ions
Answer:
There are other details missing in the question. i.e Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = p/2πε0y3 can be used, where p is the dipole moment, and y is the distance between ions. A) What is magnitude______N B) Direction? +x-direction or -x-direction C) Is this force attractive or repulsive?
A) Magnitude of electric force = 6.576 x 10 raised to power -13 N
B) Since the force direction is always dependent on the electric field and electric field = F/q, since the chlorine has a negative charge as such the direction of the electric force will be in the X - direction
C) Since the charges are of different nature, as such the force between them will be ATTRACTIVE.
Explanation:
The detailed steps is shown in the attachment
Answer:
The equilibrium partial pressure of O2 is 0.545 atm
Explanation:
Step 1: Data given
Partial pressure of SO2 = 0.409 atm
Partial pressure of O2 = 0.601 atm
At equilibrium, the partial pressure of SO2 was 0.297 atm.
Step 2: The balanced equation
2SO2 + O2 ⇆ 2SO3
Step 3: The initial pressure
pSO2 = 0.409 atm
pO2 = 0.601 atm
pSO3 = 0 atm
Step 4: Calculate the pressure at the equilibrium
pSO2 = 0.409 - 2X atm
pO2 = 0.601 - X atm
pSO3 = 2X
pSO2 = 0.409 - 2X atm = 0.297
X = 0.056 atm
pO2 = 0.601 - 0.056 = 0.545 atm
pSO3 = 2*0.056 = 0.112 atm
Step 5: Calculate Kp
Kp = (pSO3)²/((pO2)*(pSO2)²)
Kp = (0.112²) / (0.545 * 0.297²)
Kp = 0.261
The equilibrium partial pressure of O2 is 0.545 atm
