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Leona [35]
3 years ago
7

In tne equation below identify the bronsted lowry acid bronsted lowry base conjugate acid conjugate base

Chemistry
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

  • <em>Brønsted-Lowry acid: HNO₂</em>
  • <em>Brønsted-Lowry base: NH₃</em>
  • <em>Conjugate acid: NH₄⁺</em>
  • <em>Conjugate base: NO₂⁻</em>

Explanation:

The equation is:

                 HNO_2(aq)+NH_3(aq)\rightarrow NH4^+(aq)  + NO2^-(aq)

<em>Brønsted-Lowry acids</em>  are H⁺ donors.

<em>Brønsted-Lowry bases</em> are H⁺ acceptors.

Thus, on the left side, <em>HNO₂</em> is the acid and <em>NH₃ </em>is the base.

The <em>conjugate acids</em> and <em>conjugate bases</em> are on the right side of the equation.

The <em>conjugate acid</em> is the spieces that is formed after a base accepts the proton; thus it is <em>NH₄⁺</em>. A <em>conjugate acid</em> contains one more H atom and one more + charge than the base that formed it.

The <em>conjugate base</em> is the species that is formed after the acid donates its proton; thus, <em>NO₂⁻</em> is the <em>conjugate base</em>. A <em>conjugate base</em> contains one less H atom and one more - charge than the acid that formed it.

Summarizing:

  • Brønsted-Lowry acid: HNO₂
  • Brønsted-Lowry base: NH₃
  • Conjugate acid: NH₄⁺
  • Conjugate base: NO₂⁻

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Answer:

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Explanation:

Given data:

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0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

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3 years ago
in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
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Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

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The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

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mol of element G :

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mol ratio A : G = 0.5 : 0.25 = 2 : 1

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