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Nataly [62]
3 years ago
12

He splitting of the uranium atom is an example of ________. the splitting of the uranium atom is an example of ________. radioac

tive merge half life radioactive cleavage nuclear fusion nuclear fission
Chemistry
1 answer:
telo118 [61]3 years ago
8 0

The splitting of an atom is known as nuclear fission, in which a high-energy particle is introduced to a heavy atom to instigate the separation; heavy atoms are known to be naturally unstable due to their size, and a small catalyst is enough to tip the system in favor of splitting. The act of fission usually produces two daughter nuclei and some byproduct, such as an alpha or beta particle, etc.

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A compound that yields hydrogen ions when dissolved in a solution
Mumz [18]

A compound that yields hydrogen ions when dissolved in a solution is an acid.

An example is an <em>aqueous solution of HCl.</em>

7 0
4 years ago
A buffer is 0.282 m c6h5cooh(aq and 0.282 m na(c6h5coo(aq. calculate the ph after the addition of 0.150 moles of nitric acid to
Sindrei [870]
You have to use the Henderson-Hasselbalch equation. Keep in mind that because the Pka is given the equation changes form slightly:

PH = Pka + log[acid/base]

Step 1 (Figure out the concentrations):

0.282 M of Acid (C6H5OOH) - 0.150 M = 0.132 M of acid
0.282 M of Base (C6HCOO) + 0.150 M = 0.432 M of bas3

Step 2 (Plug into equation):

PH = Pka + log[acid/base]
PH = 4.20 + log[0.132 M/0.432 M]

PH = 3.69

7 0
4 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /
Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

t_{1} = 25 °C

t_{2} = 36,4 °C

Q = 325 J

The formula is: Q = c * m * (t_{2} - t_{1})

m = \frac{Q}{c * (t_{2} - t_{1} )}

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0
3 years ago
Which is an example of a bioresource used to build a home?
lutik1710 [3]
The answer should be A.
Hope this helps :-)
4 0
3 years ago
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