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STatiana [176]
4 years ago
12

If the line spectrum of lithium has a red line at 670.8 nm. How much energy does a a photon with this wavelength have?

Physics
1 answer:
Colt1911 [192]4 years ago
5 0
We already know the formula for finding the energy of a photon with this wavelength as:
<span>E = ħc / λ
</span>The information's that we already know are:
h = Plancks constant
   = <span>6.626x10^-34 Js
c = light speed
   = </span><span> 2.999x10^8 m/s
</span><span>λ = Wavelength of the light as given in the question
</span>   = <span>670.8x10^-9 m
E = amount of energy
Then
E = (</span>6.626x10^-34) * (2.999x10^8)/ (<span>670.8x10^-9)
    = </span><span>2.962x10^-19 J</span>
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Vinil7 [7]
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4 years ago
The speed of light in vacuum is exactly 299,792,458 m/s. A beam of light has a wavelength of 651 nm in vacuum. This light propag
sukhopar [10]

Answer:

v=2.58\times10^8m/s

Explanation:

The index of refraction is equal to the speed of light c in vacuum divided by its speed v in a substance, or n=\frac{c}{v}. For our case we want to use v=\frac{c}{n}, which for our values is equal to:

v=\frac{c}{n}=\frac{299792458m/s}{1.16}=258441774.138m/s

Which we will express with 3 significant figures (since a product or quotient must contain the same number of significant figures as the measurement with the  <em>least</em> number of significant figures):

v=2.58\times10^8m/s

4 0
3 years ago
Two different sources of radiation give the same dose equivalent in Sv. Does this mean that the radiation from each source has t
Alisiya [41]

The product of the dosage Gy and relative biological efficiency yields a radiation dose equivalent Sv (RBE).

Sv =dose in Gy * RBE Sv=dose in GyRBE

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Radiation is energy that moves through space at the speed of light from a source. This energy is coupled with an electric and magnetic field, and it exhibits wave-like qualities. Radiation is sometimes known as "electromagnetic waves."

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5 0
2 years ago
In the most common isotope of Hydrogen the nucleus is made out of a single proton. When this Hydrogen atom is neutral, a single
FinnZ [79.3K]

Answer:

The ratio of electric force to the gravitational force is 2.27\times 10^{39}

Explanation:

It is given that,

Distance between electron and proton, r=4.53\ A=4.53\times 10^{-10}\ m

Electric force is given by :

F_e=k\dfrac{q_1q_2}{r^2}

Gravitational force is given by :

F_g=G\dfrac{m_1m_2}{r^2}

Where

m_1 is mass of electron, m_1=9.1\times 10^{-31}\ kg

m_2 is mass of proton, m_2=1.67\times 10^{-27}\ kg

q_1 is charge on electron, q_1=-1.6\times 10^{-19}\ kg

q_2 is charge on proton, q_2=1.6\times 10^{-19}\ kg

\dfrac{F_e}{F_g}=\dfrac{kq_1q_2}{Gm_1m_2}

\dfrac{F_e}{F_g}=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}

\dfrac{F_e}{F_g}=2.27\times 10^{39}

So, the ratio of electric force to the gravitational force is 2.27\times 10^{39}. Hence, this is the required solution.

3 0
3 years ago
A veritical brass rod of circular section is loaded by placing a 10 kg wt on top of it .if it's length is 1 m. it's radius of cr
Inga [223]

Answer:

4.37 * 10^-4 J

Explanation:

Energy stored :

mgΔl / 2

m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m

Δl = mgl / πr²Y

Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m

Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10

Δl = 98 / 3.5 * π * 10^6

Δl = 0.00000891267

Energy stored :

mgΔl / 2

(10 * 9.8 * 0.00000891267) / 2

= 0.00043672083 J

4.37 * 10^-4 J

3 0
3 years ago
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