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torisob [31]
3 years ago
6

What life process requires specialized cells in multicellular organisms

Physics
1 answer:
worty [1.4K]3 years ago
4 0
The most probable answer for this question would be that almost every life process requires specialized cells in multicellular organisms. To simply put it, cells of multicellular organisms are specialized in a way that they are all grouped into their respective tissues and these tissues are all grouped into their respective organs and these organs are all grouped together into their respective systems and these systems make up the multicellular organisms. These systems have their own functions in maintaining and sustaining the life that the organisms has. The organs have their own functions as well, thus specialized cells are mostly needed in respiration, digestion, circulation, movement, excretion, reproduction, immunity, coordination, and synthesis.
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The is true because I said so
7 0
2 years ago
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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800 N on him. The
uysha [10]

Answer:

f = 692 N

Explanation:

given data:

f =800N

a =1.2 m s^{2}

m= 90 kg

from newton's second law

net force F_{net} =\sum F = F_1 +F_2 +..... = ma

therefore we have from above equationF_{net} = F -f = ma

ma =F - f

putting all value to get force of friction

1.2*90 = 800 - f

f = 692 N

8 0
3 years ago
Which of the following is not a step in the inquiry process
padilas [110]

"The process used by scientific investigations is the scientific method. This involves making an observation, stating a question, formulating a hypothesis, conducting an experiment and analyzing the results to form a conclusion. "

I would most likely go with B. but im not 100% sure

8 0
4 years ago
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
3 years ago
Ideally, the resistance of an ammeter should be:
pav-90 [236]
Ideally the resistance should be ZERO
7 0
3 years ago
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