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3 years ago

Friction is generated when ______ interfere with each other on sliding surfaces. ...?

1 answer:

5 0

<span>According to its definition, friction is generated when atoms interfere with each other on sliding surfaces.</span>

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Q1: An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical

gizmo_the_mogwai [7]

Answer:

a) F= 0,19 [N] according to problem statement

b) F = 0,19*10⁹ [N] using the right value of K

Explanation:

The force between two electric charges is according to Coulomb´s law is:

F = K * q₁*q₂ / d² where q₁ and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant K = 8,988100*10⁹ N.m²/C². The problem establishes to use K = 8,988100 N.m²/C².

NOTE: To value of is : K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹

Then:

F = 8,988100 * 1,2* 0,36 / (4,5)² [ N*m²/C² ] * [ C*C*/m²]

F = 3,882859/ 20,25 [N]

F= 0,19 [N]

The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies

4 0

3 years ago

What is the moment of inertia of the object starting from rest if it has a final velocity of 5.9 m/s? Express the moment of iner

Bogdan [553]

Answer:

The moment of inertia is I = 0.126*R^2*M

Explanation:

We can calculate the moment of inertia of an object that starts from rest and has a final velocity using the energy conservation equation, as follows:

Ek1 + Ep1 = Ek2 + Ep2, where

Ek1 = kinetic energy of the object before to roll down

Ep1 = potential energy of the object

Ek2 = kinetic energy when the object comes down

Ep2 = potential energy of the object at the bottom

We have the follow:

Ek1 = 0

Ep1 = M*g*h

Ek2 = ((I*w)/2) + ((M*v^2)/2)

Ep2 = 0

Replacing values:

0 + M*g*h = ((I*w)/2) + ((M*v^2)/2) + 0

where:

M = mass of the object

g = gravitational acceleration

I = moment of the inertia

w = angular velocity = v/R

h = height

M*g*h = ((1/2) * I * (v^2/R^2)) + ((M*v^2)/2)

M*9.8*2 = (I*(5.9^2)/(2*R^2)) + ((5.9^2 * M)/2)

19.6 * M = ((17.4*I)/R^2) + 17.4*M

Clearing I, we have:

I = 0.126*R^2*M

5 0

3 years ago

The idea is to get as much EMF produced from the sprinter running through it. If you were the Olympic coach on a year when there

never [62]

Answer:

the greater the speed, the greater the electromotive force

* The metal pole must be parallel to the field

* you must keep the ball of the field

Explanation:

To determine the advice to the runners, let's use the Farad equation to and

fem = -N $\frac{ d \phi}{dt}$ = -N $\frac{ B A Cos \theta }{dt}$

how the runners are moving

fi = B l x

fem = -N B l v

therefore the advice we can give are:

* the greater the speed, the greater the electromotive force

* The metal pole must be parallel to the field

* you must keep the ball of the field

3 0

3 years ago

How many centimeters are there in a stick 3.4 meters long?

levacccp [35]

Answer:

It's 340 centimeters.

Explanation:

Multiply it by 100

4 0

2 years ago

Read 2 more answers

A roller coaster has the most ____ energy at the top of a hill and the most ____ energy at the bottom.

scoray [572]

A is the correct answer

7 0

3 years ago

Read 2 more answers