Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-
Ca(OH)</span>₂ is <span>strong Bases</span><span>
</span>Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]
pOH = - log [ <span>5 x 10⁻⁴ ]
pOH = 3.30
pH + pOH = 14
pH + 3.30 = 14
pH = 14 - 3.30
pH = 10.7
hope this helps!</span>
When creating a Lewis-Dot structure for Carbon, you'll want to put 4 "dots"
Answer:
- <u>Tellurium (Te) and iodine (I) are two elements </u><em><u>next to each other that have decreasing atomic masses.</u></em>
Explanation:
The <em>atomic mass</em> of tellurium (Te) is 127.60 g/mol and the atomic mass of iodine (I) is 126.904 g/mol; so, in spite of iodine being to the right of tellurium in the periodic table (because the atomic number of iodine is bigger than the atomic number of tellurium), the atomic mass of iodine is less than the atomic mass of tellurium.
The elements are arranged in increasing order of atomic number in the periodic table.
The atomic number is equal to the number of protons and the mass number is the sum of the protons and neutrons.
The mass number, except for the mass defect, represents the atomic mass of a particular isotope. But the atomic mass of an element is the weighted average of the atomic masses of the different natural isotopes of the element.
Normally, as the atomic number increases, you find that the atomic mass increases, so most of the elements in the periodic table, which as said are arranged in icreasing atomic number order, match with increasing atomic masses. But the relative isotope abundaces of the elements can change that.
It is the case that the most common isotopes of tellurium have atomic masses 128 amu and 130 amu, whilst most common isotopes of iodine have an atomic mass 127 amu. As result, tellurium has an average atomic mass of 127.60 g/mol whilst iodine has an average atomic mass of 126.904 g/mol.
Answer:
% weight of nickle = 24 %
Explanation:
molar mass of Nickel Sulfamate (Ni(SO₃NH₂)₂) = 250.87 g/mol
Solution
1st we write down the molar mass of Ni
molar mass of Ni = 59 g/mol
now we write down the number of moles of Ni in (Ni(SO₃NH₂)₂)
number of moles of Ni = 1 mol
Now we calculate the mass of nickle present in (Ni(SO₃NH₂)₂)
<em> mass = moles × molar mass</em>
mass = 1 mol × 59 g/mol
mass = 59 g
now we calculate the % weight of nickle in (Ni(SO₃NH₂)₂)
<em> % weight = (weight of element ÷ total weight) × 100</em>
% weight of nickle = (59 ÷ 250.87) × 100
% weight of nickle = 0.24 × 100
% weight of nickle = 24 %
