A composite material is to be designed with epoxy (Em 3.5 GPa) and unidirectional fibers. The longitudinal elastic modulus of th
1 answer:
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Answer:
torque is 1.7 * Nm
Explanation:
Given data
turns n = 1000 turns
radius r = 12 cm
current I = 15A
magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to find out
the torque on the loop
solution
we know that torque on the loop is
torque = N* I* A*B* sinθ
here area A = πr² = π(0.12)²
put all value
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25
torque = 0.0166 N m
torque is 1.7 * Nm