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4 years ago

15

An organic compound is a compound that usually contains carbon and hydrogen, and that is found in living organisms. True or Fals

e

1 answer:

Assoli18 [71]4 years ago

7 0

This statement is true. Organic compounds hold carbon and hydrogen along with oxygen and nitrogen.

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1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it

spin [16.1K]

Answer:

Explanation:

I got everything but i. Don't know why but it's eluding me. So let's do everything but that.

a. PE = mgh so

PE = (2.5)(98)(14) and

PE = 340 J

b. $KE=\frac{1}{2}mv^2$ so

$KE=\frac{1}{2}(2.5)(14)^2$ and

KE = 250 J

c. TE = KE + PE so

TE = 340 + 250 and

TE = 590 J

d. PE at 8.7 m:

PE = (2.5)(9.8)(8.7) and

PE = 210 J

e. The KE at the same height:

TE = KE + PE and

590 = KE + 210 so

KE = 380 J

f. The velocity at that height:

$380=\frac{1}{2}(2.5)v^2$ and

$v=\sqrt{\frac{2(380)}{2.5} }$ so

v = 17 m/s

g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:

590 = KE + PE and

PE = (2.5)(9.8)(11.6) so

PE = 280 then

590 = KE + 280 so

KE = 310 then

$310=\frac{1}{2}(2.5)v^2$ and

$v=\sqrt{\frac{2(310)}{2.5} }$ so

v = 16 m/s

h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:

$v=v_0+at$ and

26 = 0 + 9.8t and

26 = 9.8t so the time at 26 m/s is

t = 2.7 seconds. Now we use that in the equation for displacement:

Δx = $v_0t+\frac{1}{2}at^2$ and filling in the time the object was at 26 m/s:

Δx = 0t + $\frac{1}{2}(-9.8)2.7)^2$ so

Δx = 36 m

i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.

4 0

3 years ago

How would changes in the rotation and revolution of the Earth and Moon affect life on Earth?

ehidna [41]

Answer:

it would mess up our circadian rhythm which is our internal clock that tells us when we should be going to sleep

7 0

3 years ago

You are given two infinite, parallel wires each carrying current I. The wires are separated by a distance d, and the current in

hoa [83]

Answer:F/L = μ0*I²/2πd

Explanation:

Both wires carries current of the value (I) and are separated by the distance (d).

The length of both wires is (L).

The first wire creates a magnetic field of the magnitude according to Bio-savart law

B=(Uo * I)/2πd

This magnetic field has the ability to exert a force F on the second wire.

This force (F) is given as

F=BIL* sin θ

θ here is 90 because the magnetic field is perpendicular to the length of the second wire.

Thus the value of sin 90 = 1

Hence F= BIL

But B=(Uo * I)/2πd.

We have that F= B=[(Uo * I)/2πd] x IL

Thus we have that F= [Uo* I²/2πd] x L

By rearranging, and bringing L to the left hand side of the equation, we have that

F/L = [Uo* I²/2πd]

6 0

3 years ago

In the space around a permanent magnet, where is the magnetic field the strongest?

BlackZzzverrR [31]

near the north and south poles of the magnet

Explanation:

Magnetic fields around a permanent magnet is strongest near the north and south poles of the magnet.

Magnetic fields are the region of space around a magnet where magnetic effects are felt.

This is as a result of a force field that surrounds the magnet.
Magnetic fields are strongest within the magnet.
Also, externally, they are strongest at the poles of a magnet.
Around the poles, magnetic lines of force leaves and enters a magnet.

learn more;

Electromagnet brainly.com/question/2191993

#learnwithBrainly

6 0

3 years ago

A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volume is occupied by w

rjkz [21]

Answer:

(a) Volume of the tank is $6.47\times 10^{- 3}\ m^{3}$

(b) Temperature is $371^{\circ}C$

Pressure is 21.3 kPa

(c) The change in internal energy is 1373.54 kJ/kg

Solution:

As per the question:

Mass of liquid in the tank, m = 1.4 kg

Temperature, T = $200^{\circ}C$

Volume occupied by water, V = 25% $V_{t}$ = 0.25 $V_{t}$

Volume occupied by air, V' = 75% $V_{t}$

where

$V_{t}$ = Volume of tank

Now,

(a) In order to calculate the volume of the tank, we make use of the steam table for specific volume at as given temperature:

At $200^{\circ}C$ , the specific volume, v = 0.001157 $m^{3}/kg$

At $200^{\circ}C$ , the internal energy, u = 850.46 kJ/kg

Now, Volume of water, V = mv = $1.4\times 0.001157 = 1.62\times 10^{- 3} m^{3}$

Thus

$V = 0.25V_{t}$

$V_{t} = \frac{1.62\times 10^{- 3}}{0.25} = 6.47\times 10^{- 3}\ m^{3}$

(b) For the final temperature and pressure, we calculate the specific volume, v' and then find the corresponding temperature and pressure from the steam table:

v' = $\frac{V_{t}}{m} = \frac{6.47\times 10^{- 3}}{1.4} = 4.63\times 10^{- 3}\ m^{3}/kg$

The corresponding temperature to this specific volume, T' = $371^{\circ}C$

The corresponding pressure to this specific volume, P' = 21.3 kPa

The corresponding internal energy to this specific volume, u' = 2224 kJ/kg

(c) The change in the internal energy of water is given by:

$\Delta U = u' - u = 2224 - 850.46 = 1373.54 kJ/kg$

3 0

3 years ago