Answer:
It increases by four times the initial amplitude.
Explanation:
The amplitude of a sounde is inversely proportional to the square of the distance between the listener and the sound source:
In this problem, the distance is decreased to hald the initial distance, so we can write
therefore, the new amplitude will be
So, the amplitude increases by a factor 4.
You could talk about how the planets spin around the sun, how the universe has galaxies, and we are in the milky way. Blue shift and red shift,etc?
Answer:
The period of that same pendulum on the moon is 12.0 seconds.
Explanation:
To determine the period of that same pendulum on the moon,
First, we will determine the value of g (which is a measure of the strength of Earth's gravity) on the Moon. Let the value of g on the Moon be .
From the question, the strength of earth’s gravity is only 1/6th of the normal value. The normal value of g is 9.8 m/s²
∴ =
= 1.63 m/s²
From the question, T=2π√L/g
We can write that,
.......... (1)
Where is the period of the pendulum on Earth and is the measure of the strength of Earth's gravity
and
.......... (2)
Where is the period of the pendulum on Moon and is the measure of the strength of Earth's gravity on the Moon.
Since we are to determine the period of the same pendulum on the moon, then, and are constants.
Dividing equation (1) by (2), we get
From the question,
= 9.8 m/s²
= 1.63 m/s²
= ??
From,
∴
Hence, the period of that same pendulum on the moon is 12.0 seconds.
Answer:
g = 9.8 [m/s²]
Explanation:
To solve this problem we must remember that the potential energy is defined as the product of mass by gravitational acceleration by the height or elevation with respect to a reference level.
Ep = m*g*h
where:
Ep = potential energy = 235.2 [J]
m = mass of the book = 6 [kg]
g = gravity acceleration [m/s²]
h = elevation = 4 [m]
Now replacing these values:
235.2 = 6*g*4
g = 235.2/(24)
g = 9.8 [m/s²]
Answer:
D. 5.18 x 10⁻¹²
Explanation:
= rate at which sun radiates energy = 3.92 x 10²⁶ W
M = mass of sun = 1.99 x 10³⁰ kg
= rate at which sun's mass is lost
c = speed of light
Energy is given as
E = m c²
Taking derivative both side relative to "t"
= 4.4 x 10⁹ kg/s
t = time interval = 75 yrs = 75 x 365 days = 75 x 365 x 24 hours = 75 x 365 x 24 x 3600 sec = 2.4 x 10⁹ sec
= mass lost
mass lost is given as
m = 10.56 x 10¹⁸ kg
fraction is given as
fraction =
fraction =
fraction = 5.18 x 10⁻¹²