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dimulka [17.4K]
3 years ago
6

Which method is the typical first step when scientists communicate their scientific results? placing the results on an Internet

site to maximize readership distributing the results in press releases to make them well established submitting the results to a scientific journal for a peer review declaring the results in a TV interview for public feedback
Physics
2 answers:
Talja [164]3 years ago
6 0

Answer:

Option C (submitting the results to a scientific journal for a peer review) is the correct choice.

Explanation:

  • If a researcher or a scientist decides to transmit his conclusions depends on a variety of considerations. At either the conclusion of the day, the scientist should concentrate on the final use of an individual's findings before settling on how to transmit it, either through science papers, announcements at professional journals, or personally with the public.
  • Scientists often prefer to submit their articles to professional conferences rather than just going via scientific publications.

The other solutions offered are not relevant to the situation in question. But the latter is the best answer.

tangare [24]3 years ago
3 0

Answer:

it is letter c

Explanation:

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Marys airplane trip took 5.8 hours for one-half of that time, the airplane flew at a constant speed of 640 miles per hour and fo
Olenka [21]
Distance is speed x time.  Half of the trip is 5.8/2 = 2.9hrs.
640 x 2.9 = 1856mi
580 x 2.9 = 1682mi
1856mi+1682mi=3538mi.

You could also calculate her average speed.  This is easy since it was divided in two equal time slices.  Average Speed = (640+580)/2 = 610mi/hr
Now 610mi/hr x 5.8hrs = 3538mi
7 0
3 years ago
A Styrofoam ball has just been shot straight up. Air resistance is not negligible (free body diagram)
timofeeve [1]

In a free body diagram for an object projected upwards;

  • the acceleration due to gravity on the object is always directed downwards.
  • the velocity of the object is always in the direction of the object's motion.

An object projected upwards is subjected to influence of acceleration due to gravity.

As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.

To construct a free body diagram for this motion, we consider the following;

  • the acceleration due to gravity on the object is always directed downwards
  • the velocity of the object is always in the direction of the object's motion.

<u>For instance:</u>

upward motion for velocity  ↑        downward motion for velocity  ↓

                                              ↑                                                            ↓

                                              ↑                                                            ↓

acceleration due to gravity ↓

                                             ↓

                                             ↓

Learn more here: brainly.com/question/13235430

5 0
3 years ago
9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in
Varvara68 [4.7K]

Answer:

4.4 M/s

Explanation:

6 0
3 years ago
A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a
UNO [17]

Answer:

P_{avg} = 6.283*10^{-9} \ W

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

\phi = \frac{\mu_o Ic }{2 \pi} In (\frac{b+a}{b})

where;

E= \frac{d \phi}{dt}

E = \frac{\mu_o}{2 \pi}c In (\frac{b+a}{a}) I_o \omega cos \omega t

E_{rms} =   \frac { {\frac{\mu_o \ c}{2 \pi} In (\frac{b+a}{a}) I_o (2 \pi f)}}{\sqrt{2}}

Replacing our values into above equation; we have:

E_{rms} =   \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}

E_{rms} =   \frac {8.98909588*10^{-4} }{\sqrt{2}}

E_{rms} =   6.356*10^{-4} \ V

Then the P_{avg is calculated as:

P_{avg} = \frac{E^2}{R}

P_{avg} = \frac{(6.356*10^{-4})^2}{64.3}

P_{avg} = 6.283*10^{-9} \ W

6 0
3 years ago
Heat energy is:
Archy [21]
I claim that it's d moving electrons.
6 0
3 years ago
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