Answer:
The correct option is (b) 0.333.
Step-by-step explanation:
The data provided is as follows:
Hepatitis C No hepatitis C Total
No Tattoos 5 50 55
1 Tattoo 10 210 220
> 1 Tattoo 15 150 165
Total 30 410 440
The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.
![P(E)=\frac{n(E)}{N}](https://tex.z-dn.net/?f=P%28E%29%3D%5Cfrac%7Bn%28E%29%7D%7BN%7D)
The condition probability of an event <em>A</em> provided that another event <em>X</em> has already occurred is:
![P(A|X)=\frac{P(A\cap X)}{P(X)}](https://tex.z-dn.net/?f=P%28A%7CX%29%3D%5Cfrac%7BP%28A%5Ccap%20X%29%7D%7BP%28X%29%7D)
The number of people who has hepatitis C is:
n (Hepatitis C) = 30
The number of people who has hepatitis C and one tattoo is:
n (Hepatitis C and 1 Tattoo) = 10
Compute the probability that he or she has hepatitis C, given that he or she has one tattoo as follows:
![P(\text{Hepatitis C} |\text{1 Tattoo})=\frac{n(\text{Hepatitis C and 1 Tattoo})}{n(\text{1 Tattoo})}](https://tex.z-dn.net/?f=P%28%5Ctext%7BHepatitis%20C%7D%20%7C%5Ctext%7B1%20Tattoo%7D%29%3D%5Cfrac%7Bn%28%5Ctext%7BHepatitis%20C%20and%201%20Tattoo%7D%29%7D%7Bn%28%5Ctext%7B1%20Tattoo%7D%29%7D)
![=\frac{10}{30}\\\\=\frac{1}{3}\\\\=0.333](https://tex.z-dn.net/?f=%3D%5Cfrac%7B10%7D%7B30%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%3D0.333)
Thus, the correct option is (b).
The graph to pick is D because it's decreasing by one and starts at 10
The 6 is in the ones places, and the 2 is in the hundreths place.