2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g
Answer:
Explanation:
The expected product is MgO, so the 1-to-1 mole ratio Mg to O in the product is all that is required.
32 electrons. as the orbitals get father away from the nucleus, they hold more electrons.
Answer:
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Explanation:
