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ANEK [815]
3 years ago
10

A large crane consists of a 20 m, 3,000 kg arm that extends horizontally on top of a vertical tower. The arm extends 15 m toward

s the lifting end and 5 m towards the counterweight. If the crane is to lift a 5,000 kg load, what must the weight of the counterweight be in order to maintain static equilibrium
Physics
1 answer:
Anni [7]3 years ago
7 0

Answer:

m=18000kg

Explanation:

From the question we are told that:

Crane Length l=20m

Crane Mass m_a=3000kg

Arm extension at lifting end l_l=15m

Arm extension at counter weight end l_c=5m

Load M_l=5000kg

Generally the equation for Torque Balance is mathematically given by

T_1 *l_c-(m_a*g) *l_c-(T_2)*l_l=0

mg*5 *-(3000*9.8) *5-(5000*9.8)*15=0

m=18000kg

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