Answer:
Training is a way for employers to provide tools to enable employees to protect themselves and others from injuries.
Explanation:
Answer:
I think true
Explanation:
Well I mean...we cant see the future. Certain things will be achieveable in different ganerations like going on mars
Answer:
The volume up to cylindrical portion is approx 32355 liters.
Explanation:
The tank is shown in the attached figure below
The volume of the whole tank is is sum of the following volumes
1) Hemisphere top
Volume of hemispherical top of radius 'r' is

2) Cylindrical Middle section
Volume of cylindrical middle portion of radius 'r' and height 'h'

3) Conical bottom
Volume of conical bottom of radius'r' and angle
is

Applying the given values we obtain the volume of the container up to cylinder is
Hence the capacity in liters is 
Answer:
The mass flow rate of cooling water required to cool the refrigerant is
.
Explanation:
A condenser is a heat exchanger used to cool working fluid (Refrigerant 134a) at the expense of cooling fluid (water), which works usually at steady state. Let suppose that there is no heat interactions between condenser and surroundings.The condenser is modelled after the First Law of Thermodynamics, which states:



The mass flow rate of the cooling water is now cleared:

Given that
,
,
and
, the mass flow of the cooling water is:


The mass flow rate of cooling water required to cool the refrigerant is
.
Answer:
q = 1.73 W
Explanation:
given data
small end = 5 cm
large end = 10 cm
high = 15 cm
small end is held = 600 K
large end at = 300 K
thermal conductivity of asbestos = 0.173 W/mK
solution
first we will get here side of cross section that is express as
...............1
here x is distance from small end and S1 is side of square at small end
and S2 is side of square of large end and L is length
put here value and we get
S = 5 +
S =
m
and
now we get here Area of section at distance x is
area A = S² ...............2
area A =
m²
and
now we take here small length dx and temperature difference is dt
so as per fourier law
heat conduction is express as
heat conduction q =
...............3
put here value and we get
heat conduction q =
it will be express as
now we intergrate it with limit 0 to 0.15 and take temp 600 to 300 K
solve it and we get
q (30) = (0.173) × (600 - 300)
q = 1.73 W