Answer:
The condition does not hold for a compression test
Explanation:
For a compression test the engineering stress - strain curve is higher than the actual stress-strain curve and this is because the force needed in compression is higher than the force needed during Tension. The higher the force in compression leads to increase in the area therefore for the same scale of stress the there is more stress on the Engineering curve making it higher than the actual curve.
<em>Hence the condition of : on the same scale for stress, the tensile true stress-true strain curve is higher than the engineering stress-engineering strain curve.</em><em> </em>does not hold for compression test
Answer:
Explanation:
To solve this problem we use the expression for the temperature film
Then, we have to compute the Reynolds number
Re<5*10^{5}, hence, this case if about a laminar flow.
Then, we compute the Nusselt number
but we also now that
but the average heat transfer coefficient is h=2hx
h=2(8.48)=16.97W/m^{2}K
Finally we have that the heat transfer is
In this solution we took values for water properties of
v=16.96*10^{-6}m^{2}s
Pr=0.699
k=26.56*10^{-3}W/mK
A=1*0.5m^{2}
I hope this is useful for you
regards
The formal procedure for taking equipment out of service and ensuring it cannot be operated until an authorized person has returned it to service is
Explanation:
Answer:
look below at illustrated diagrams and solution for Mz=1.13kN
Answer:
Tension in wire will be
Explanation:
We have given seed of the transverse wave v = 400 m/sec
Linear density = 0.10 g/cm
We know that 1 gram = 0.001 kg
And 1 cm = 0.01 m
So
We know that speed of wave is given by , here T is tension in the wire
So
Squaring both side
T =
So tension in wire will be