X+y=2
y=1/2x+5
x+ y=2
-1/2x+y =5

Subtracting the two equations;
3/2x=-3
x=-2
Replacing in the first equation;
-2+y=2
y=4
They would intersect at (-2, 4)

4 0

3 years ago

Read 2 more answers

if I set off for the market,a distance of 11km at 10am. And walk at an average speed of 3km per hour,At what time will I reach t

earnstyle [38]

Answer:

At 1:40 pm you will reach the market.

Step-by-step explanation:

Distance (d) = 11 km

Average speed (v) = 3 km/h

Formula:

$\rm Average \: speed = \dfrac{Distance}{Time} \\ \\ \rm 3 = \dfrac{11}{t} \\ \\ \rm t = \dfrac{11}{3} \\ \\ \rm t = 3 \frac{2}{3} \\ \\ \rm t = 3 hr \: 40min$

It will take 3 hours 40 minutes to reach the market.

So, if you set off for the market at 10 am you will reach market by 1:40 pm (10 am + 3hr 40min).

7 0

2 years ago