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Thepotemich [5.8K]
3 years ago
7

The density of corn syrup is 1.38 g/cm3.. . Which substance will float in corn syrup? A. graphite (2.16 g/cm3). B. glycerin (1.2

6 g/cm3). C. copper (8.9 g/cm3). D. silver (10.5 g/cm3)
Chemistry
2 answers:
PolarNik [594]3 years ago
7 0
"Glycerin" is the one substance among the following choices given in the question that will <span>float in corn syrup. The correct option among all the options that are given in the question is the second option or option "B". I hope that this is the answer that has actually come to your desired help.</span>
9966 [12]3 years ago
7 0

Answer: B. glycerin (1.26 g/cm3).

Explanation: The substances with higher value of density than the density of corn syrup will sink and the substances with lower value of density than the density of corn syrup will float.

A.  graphite : has a density of 2.16g/cm^3 which is higher than the density of corn syrup which is 1.38g/cm^3, Thus it will sink.

B. glycerin: has a density of 1.26g/cm^3 which is lower than the density of corn syrup which is 1.38g/cm^3, Thus it will float.

C. copper :has a density of 8.9g/cm^3 which is higher than the density of corn syrup which is 1.38g/cm^3, Thus it will sink.

D. silver: has a density of 10.5g/cm^3 which is higher than the density of corn syrup which is 1.38g/cm^3, Thus it will sink.

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Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/
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The answer to your question is:  ΔHrxm = -23.9 kJ

Explanation:

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2Fe(s)+3/2O2(g)→Fe2O3(s),  ΔH = -824.2 kJ     (1)

    CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ   (2)

Reaction:

                          Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)  

We invert (1) and change the sign of  ΔH

        Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

We multiply (2) by 3

      3(  CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ)   (2)

      3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

We add (1) and (2)

Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

Fe2O3(s) +  3CO(g)+3/2O2(g)  →  2Fe(s)+3/2O2 + 3CO2(g)    

Simplify

    Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)    and ΔHrxm = -23.9 kJ

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