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3 years ago

What pressure is required to compress 156.0 liters of air at 2.00 atmosphere into a cylinder

Chemistry

1 answer:

garik1379 [7]3 years ago

7 0

Answer:

option B.

Explanation:

Given,

V₁ = 156 L

P₁ =2 atm

Now, in the cylinder

P₂ = ?

V₂ = 36

Using relation between pressure and volume

$\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}$

$\dfrac{2}{36}=\dfrac{P_2}{156}$

$P_2 = 8.67\ atm$

Hence, pressure is equal to 8.67 atm.

Hence, the correct answer is option B.

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Which property best indicates that a compound contains an ionic bond?

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Ionic bond is characterized by the complete transfer of valence electrons between atoms. In this kind of bond, a metal loses its electron in order to become a cation while the nonmetal accept the electron resulting to an anion.

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Which element would you expect to have the largest radius based on the Periodic Table?

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Answer:

Lead

Explanation:

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3 years ago

We know that for a given reaction when the temperature increases from 100 k to 200 k the rate constant doubles. What is the acti

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Answer:

The activation energy of the reaction is 1.152 kJ/mol.

Explanation:

Activation energy is the minimum amount which is absorbed by the reactant molecules to undergo chemical reaction.

Initial temperature of reaction = $T_1=100 K$

Final temperature of reaction = $T_2=200 K$

Initial rate of the reaction at 100 k = $K_1=k$

Final rate of the reaction at 200 k = $K_2=2k$

Activation energy is calculated from the formula:

$\log\frac{K_2}{K_1}=\frac{E_a}{2.303\times R}(\frac{T_2-T_1}{T_1T_2})$

R = Universal gas constant = 8.314 J/ K mol

$\log\frac{2k}{k}=\frac{E_a}{2.303\times 8.314 J/K mol}(\frac{200 K-100K}{200 K\times 100K})$

$E_a=1,152.772 J/mol=1.152 kJ/mol$

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3 years ago

Which process of a volume of solution of known concentration to determine the concentration of another solution

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Answer: Titration

Explanation:

Titration is a method of quantitative analysis, by which a student, with standard volumetric equipment, burettes, and pipettes, can achieve very precise, and accurate results. It is also known as

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3 years ago

A sample of carbon dioxide gas has a density of g/L at a pressure of 0.889 atm and a temperature of 55.0 °C. Assume ideal behavi

gladu [14]

Answer:

163.5 °C

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 686 mL.

Initial temperature (T1) = 55 °C.

Final volume (V2) = 913 mL

Initial pressure (P1) = final pressure (P2) = 0.889 atm

Final temperature (T2) =.?

Next, we shall convert celsius temperature to Kelvin temperature.

This can be done as shown below:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 55 °C.

Initial temperature (T1) = 55 °C + 273

Initial temperature (T1) = 328 K

Next, we shall determine the new temperature of the gas.

Since the pressure is constant, we shall determine the new temperature as follow:

V1/T1 = V2 /T2

Initial volume (V1) = 686 mL.

Final volume (V2) = 913 mL

Initial temperature (T1) = 328 K

Final temperature (T2) =.?

V1/T1 = V2 /T2

686/328 = 913/T2

Cross multiply

686 x T2 = 328 x 913

Divide both side by 686

T2 = (328 x 913)/686

T2 = 436.5 K

Finally, we shall convert Kelvin temperature to celsius temperature.

This can be done as shown below:

Temperature (°C) = Temperature (K) – 273

T (°C) = T(K) – 273

T(K) = 436.5 K

T (°C) = 436.5 – 273

T (°C) = 163.5 °C

Therefore, the temperature of the gas sample is 163.5 °C.

5 0

3 years ago