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saul85 [17]
3 years ago
11

United States

Chemistry
1 answer:
Korolek [52]3 years ago
3 0

What are you wanting????

or is this a statement?

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Determine the [OH-], pH, and pOH of a solution with a [H+] of 0.090 M at 25 °C. [OH-] = pH = pOH = 0 POH =
ValentinkaMS [17]

Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95

The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

5 0
2 years ago
Read 2 more answers
Solid Iron (III) reacts with oxygen gas to form iron (III) oxide, which is the compound we see when rust is present. Based on th
Sunny_sXe [5.5K]

Answer:

Option E is correct. none of the above is correct

Explanation:

Step 1: Data given

Solid Iron (III) = Fe^3+

iron (III) oxide = Fe2O3

Molar mass Fe = 55.845 g/mol

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation:

4Fe + 3O2 → 2Fe2O3

4 moles of iron will need 2 moles of oxygen gas to fully react

⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react

B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.

⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3

C.9 moles of oxygen can produce 9 moles of Iron (III) oxide

⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3

D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.

⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3

E.none of the above

6 0
3 years ago
Be sure to answer all parts. part 1 out of 4 how many nucleophilic centers are present in methanol (ch3oh)?
leva [86]

Answer:

              One nucleophilic center

Explanation;

Nucleophile:

                    Nucleophile is a substance which is nucleus loving in nature (<em>Nucleo</em>; Nucleus , <em>phile</em>; Loving). It is known as a specie which donates a lone pair of electrons to electrophile (electron loving) in a chemical reaction.

                    Thus, Nucleophile is the region of higher electron density in a molecule and attacks on the lower electron density region of another molecule. Also, the nucleophile can also contain a negative charge.

Number of Nucleophilic centers in Methanol:

The chemical structure of Methanol is attached below and it can be observed that the oxygen atom is containing two lone pair of electrons. Hence, the oxygen atom can act as a nucleophilic center. Therefore, there is only one nucleophilic center in methanol.

                        H₃C-OH  +  H₃C-Br     →        H₃C-O-CH₃  +  HBr

In above reaction methanol is acting as a nucleophile and is attacking on electrophilic center (Carbon) of methyl bromide yielding dimethyl ether.

8 0
3 years ago
Read 2 more answers
scientist have found many marine fossils on the mountain far from any ocean or sea what is the best explanation for these fossil
DaniilM [7]

The best explanation, though it's controversial, is that a great flood had once covered the earth for a brief period of time.

8 0
3 years ago
In the titration between potassium iodate and the sodium thiosulfate solution, if the titration is not performed immediately aft
N76 [4]

Answer:

The calculated concentration of sodium thiosulphate solution will be less than the actual value.

Explanation:

When IO3^2- solution is added to KI solution, I2 gas is released ,then sulphuric acid is now added to facilitate reduction. In order to prevent the escape of iodine (I2) gas ,the solution must immediately be titrated with thiosulphate.

If the solution is not immediately titrated with thiosulphate, the concentration of iodine available in the system decreases. When this occurs, it will also cause a decrease in the amount of iodine available to react with thiosulphate thus decreasing the concentration of thiosulphate obtained from calculation

5 0
3 years ago
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