Evaluate the function at the given point. x=-1

Mathematics

1 answer:

Ymorist [56]3 years ago

8 0

Answer:

To evaluate a function, substitute the input (the given number or expression) for the function's variable (place holder, x). Replace the x with the number or expression. Given the function f (x) = 3x - 5, find f (4). Solution: Substitute 4 into the function in place of x.

Step-by-step explanation:

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Hwong can fit 12 packets of coffee in a small box and 50 packets of coffee in a large box. He had 10 small boxes of coffee and w

nasty-shy [4]

Hwong could fill 12 packets of coffee in small boxes:

He has 10 boxes, so 10 x 12 = 120 packets total

Hwong's packets of coffee in the large boxes:

He can fit 50 packets into the boxes, so 120/50 = 2 large boxes and a remaining 20 packets of coffee

Therefore, Hwong can fit 12 packets of coffee to 1 small box and 8 packets to the other small box

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3 years ago

Read 2 more answers

8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member

tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

So the number of ways a committee of 5 students can be chosen from a student council of 30 students= $^{30}C_5=\dfrac{30!}{5!(30-5)!}$

$=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506$

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0

2 years ago

Evaluate the following limit, if it exists : limx→0 (12xe^x−12x) / (cos(5x)−1)

Amanda [17]

Answer:

$\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}$

Step-by-step explanation:

Notice that $\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=\frac{12(0)e^{0}-12(0)}{cos(5(0))-1}=\frac{0}{0}$ , which is in indeterminate form, so we must use L'Hôpital's rule which states that $\lim_{x \to c} \frac{f(x)}{g(x)}=\lim_{x \to c} \frac{f'(x)}{g'(x)}$ . Basically, we keep differentiating the numerator and denominator until we can plug the limit in without having any discontinuities: