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denis-greek [22]
3 years ago
14

A compound is a substance composed of two or more identical molecules or in a simple way we can say it as it is a substance form

ed when two or more similar or identical chemical molecules make a bond together or it is the combination of two or more compounds.​
Physics
2 answers:
Nataly [62]3 years ago
6 0

A chemical compound is a chemical substance composed of many identical molecules (or molecular entities) composed of atoms from more than one element held together by chemical bonds. A molecule consisting of atoms of only one element is therefore not a compound.

Fittoniya [83]3 years ago
4 0

Answer:

A compound is a substance that is a composed of two or more different kinds of molecules. Compounds are held together by chemical bonds.A molecule is a group of atoms held together by covalent bonding that acts as an independent unit

Explanation:

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During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce
Anna [14]

Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m

5 0
3 years ago
Polarized light passes through a polarizer. If the electric vector of the polarized light is horizontal what, in terms of the in
Nina [5.8K]

Answer:

The intensity of the light that passes through a polarizer is 0.55I₀.

Explanation:

The intensity of the light that passes through a polarizer can be found using Malus's law:  

I = I_{0}cos^{2}(\theta)

<u>Where</u>:

I: is the intensity of the light that passes through a polarizer

I₀: is the initial intensity

θ:  is the angle between the light's initial polarization direction and the axis of the polarizer = 42°  

I = I_{0}cos^{2}(\theta) = I_{0}cos^{2}(42) = 0.55*I_{0}

Therefore, the intensity of the light that passes through a polarizer is 0.55I₀.

I hope it helps you!  

5 0
3 years ago
A 1.4 kg particle moves along an x axis, being propelled by a variable force directed along that axis. Its position is given by
mihalych1998 [28]

Answer:

The value of c is 27.4 m/s²

Explanation:

Hi there!

Let´s write the position function:

x = 3.0 m + (4.0 m/s) · t + c · t² - (1.6 m/s³) · t³

The velocity of the particle is given by the derivative of the position function with respect to time:

dx/dt = v = 4.0 m/s + 2 · c · t - 4.8 m/s³ · t²

The acceleration of the particle is the derivative of the velocity function with respect to t:

dv/dt = a = 2 · c - 9.6 m/s³ · t

The applied force at t = 3.0 s is calculated as follows:

F = m · a

Where:

F = applied force.

m = mass of the particle.

a = acceleration.

Then:

F = m · a

36 N = 1.4 kg · a

36 N / 1.4 kg = a

a = 26 m/s²

We have derived the equation of the acceleration above:

a = 2 · c - 9.6 m/s³ · t

Then, using a = 26 m/s² and t = 3.0 s, we can solve the equation for c:

26 m/s² = 2 · c - 9.6 m/s³ · 3.0 s

26 m/s² + 9.6 m/s³ · 3.0 s  = 2 · c

54.8 m/s² = 2 · c

54.8 m/s² / 2 = c

c = 27.4 m/s²

The value of c is 27.4 m/s²

4 0
4 years ago
Should the size of the test charge compare to the amount of charge that produces the field
Alla [95]

Answer:

20000000000)0000000000000

4 0
3 years ago
How does the gravitational force between two objects change if the distance
Anestetic [448]

Answer:

The Gravitational Force is reduced 4 times

Explanation:

The equation of Gravitational force follows:

F = (G*m1*m2)/r^2

Assume that G*m1*m2 = 1 and r = 1:

F = 1/1^2 = 1 N

Multiply the radius by 2

F = 1/2^2 = 1/4 N

So doubling the distance reduces the force 4 times.

7 0
3 years ago
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