Question; what causes earthquakes?
Answer; what causes earthquakes are mainly when rocks are underground and then suddenly break along a fault.
Answer:
a.18.5 m/s
b.1.98 s
Explanation:
We are given that

a.Let
be the initial velocity of the ball.
Distance,x=30 m
Height,h=1.8 m





Substitute the values





Initial velocity of the ball=18.5 m/s
b.Substitute the value then we get

t=1.98 s
Hence, the time for the ball to reach the target=1.98 s
The region marked X in the diagram shows that the objects have the same charge.
<h3>
What is conduction?</h3>
The term conduction has to do with the manner of charging in which charge is passed from one object to another. Induction involves charging objects without the objects touching each other.
The region marked X in the diagram shows that the objects have the same charge.
Learn ore about conduction:brainly.com/question/15306642
#SPJ1
Answer:
<h2>A.
6pF</h2>
Explanation:
If unknown capacitance C1, C2, C3 and C4 are connected in series to one another, their equivalent capacitance of the circuit will be expressed as shown

Given the capacitance's 3.0 pF, 2.0 pF, 5.0 pF and X pF connected in series to each other. If the equivalent capacitance of the circuit is 0.83 pF, then to get X, we will apply the formula above;

C₄ ≈ 6pF
Hence the value of the X capacitor is approximately 6pF
Answer:
. always start on the north pole and terminate (end) on the South Pole
Explanation: