Answer:
I will assume that “maximum force” implies the constant application of power P = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.
In this case the 400 hp (equivalent to 298,280 watts) is applied for time t = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:
ΔKE=Pt=(298,280)(2)=596,560 joules.
The initial kinetic energy is:
KEinitial=12mv2
=(0.5)(1600)(82)=51,200 joules.
Therefore final kinetic energy is:
KEfinal=KEinitial+ΔKE
=51,200+596,560
=647,760 joules
Therefore final vehicle velocity can be found:
KEfinal=12mv2
v=2KEfinalm−−−−−−−−√
=(2)(647,760)1600−−−−−−−−−−−√
= 28.455 m/s
Explanation:
Force is indirectly proportional to the distance. Therefore when the distance increases the force of attraction increases and the answer would be B
Answer:
what is the social problem about
Explanation:
Answer:
Explanation:
We shall apply law of conservation of momentum to know the Speed of northward moving vehicle before collision to check the veracity of driver's statement .
Let v be the velocity of composite mass after collision
Applying law of conservation of momentum in north direction
m v₂ = 2m v sin55.08
Applying law of conservation of momentum in east direction
m x 13 = 2m v cos55.08
Dividing these two equations
v₂ / 13 = tan55.08
v₂ = 13 tan55.08
= 18.62 m/s
= (18.62 x60 x 60) / 1000
= 67 km/h
= 67 x 5/8 mi/h
= 42 mi/h
So he is lieing.
