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ira [324]
3 years ago
13

Consider the circuit below, which is powered by a 6-v battery. switch s is opened at t = 0 after having been closed for a long t

ime. (a) how much energy is stored in the inductor at t = 0? 37.5 correct: your answer is correct. mj (b) what is the instantaneous rate of change of the inductor's energy at t = 0? 7.5 incorrect: your answer is incorrect. w (c) what is the average rate of change of the inductor's energy between t = 0.0 and t = 1.0 s? -.0375 correct: your answer is correct. w (d) how long does it take for the current in the inductor to reach 0.00020 times its initial value?
Physics
1 answer:
Semmy [17]3 years ago
3 0
The answer should be B 
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You will get 50pts and the check mark.
Tamiku [17]
B) A ladybug crawling forward at constant rate of 2.5 m/s
6 0
3 years ago
Read 2 more answers
A ball is dropped and bounces off the floor. Its speed is the same immediately before and immediately after the collision. Which
Korolek [52]

Answer:

option B.

Explanation:

The correct answer is option B.

when the ball drops, the velocity of the ball before the collision is v

After the collision, the velocity of the ball is the same but in the opposite direction.

Impulse delivered to the ball and the floor, in this case, is not zero.

The magnitude of the momentum remains the same but the direction of the ball changes.

7 0
3 years ago
1.<br> Kinetic energy is the energy of _____.
lorasvet [3.4K]

Explanation:

kinetic energy is energy that it possesses due to its motion.

7 0
3 years ago
You have a lightweight spring whose unstretched length is 4.0 cm. First, you attach one end of the spring to the ceiling and han
sleet_krkn [62]

Answer:

2.2nC

Explanation:

Call the amount by which the spring’s unstretched length L,

the amount it stretches while hanging x1

and the amount it stretches while on the table x2.

Combining Hooke’s law with Newton’s second law, given that the stretched spring is not accelerating,

we have mg−kx1 =0, or k = mg /x1 , where k is the spring constant. On the other hand,

applying Coulomb’s law to the second part tells us ke q2/ (L+x2)2 − kx2 = 0 or q2 = kx2(L+x2)2/ke,

where ke is the Coulomb constant. Combining these,

we get q = √(mgx2(L+x2)²/x1ke =2.2nC

4 0
3 years ago
When is a model used in science?
Mamont248 [21]
C. Both of the above
8 0
3 years ago
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