What reason best explains why metals are ductile instead of brittle

Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. Write a word amd chemical equation for this reaction.

Varvara68 [4.7K]

Answer: -

Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. The balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

Explanation: -

Chemical symbol of magnesium = Mg

Chemical formula for magnesium hydroxide = Mg(OH)₂

Chemical formula for hydrogen gas = H₂

The other reactant with Mg must be water H₂O.

Thus the balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

7 0

3 years ago

I NEED AN ANSWER TO THESE QUESTIONS ASAP!! I GOT A TEST TOMORROW ON THIS!!!

Paha777 [63]

18.The octet rule tells us that in every chemical reactions, elements will either gain or lose electrons to attain the noble gas electron configuration. This stable electron configuration is known as the octet configuration since it is composed of 8 valence. Oxygen’s electron configuration is 1s2 2s2 2p4. So when oxygen reacts with other elements to form compounds, it completes the octet configuration by taking 2 electrons from the element it reacts with

19. Actually pure metals are made up not of metal atoms but rather of closely packed cations (positively charge particles). These cations are then surrounded by a pack of mobile valence electrons which drift from one part of the metal to another. This is called metallic bond.

20. This is the energy which is needed to break a single bond. When the dissociation energy is large, this means that the compound is more stable. Since carbon to carbon bonds have high dissociation energy, therefore they are not very reactive.

21. Network solids are type of solids in which the atoms are covalently bonded to one another, so they are very stable. It takes higher temperature to melt them because breaking these covalent bonds required greater energy. Some examples are:
- Diamond
-Silicon Carbide

5 0

3 years ago

Consider the reaction Mg(s) + I2 (s) → MgI2 (s) Identify the limiting reagent in each of the reaction mixtures below:

Lapatulllka [165]

Answer:

a) Nor Mg, neither I2 is the limiting reactant.

b) I2 is the limiting reactant

c) Mg is the limiting reactant

d) Mg is the limiting reactant

e) Nor Mg, neither I2 is the limiting reactant.

f) I2 is the limiting reactant

g) Nor Mg, neither I2 is the limiting reactant.

h) I2 is the limiting reactant

i) Mg is the limiting reactant

Explanation:

Step 1: The balanced equation:

Mg(s) + I2(s) → MgI2(s)

For 1 mol of Mg we need 1 mol of I2 to produce 1 mol of MgI2

a. 100 atoms of Mg and 100 molecules of I2

We'll have the following equation:

100 Mg(s) + 100 I2(s) → 100MgI2(s)

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

b. 150 atoms of Mg and 100 molecules of I2

We'll have the following equation:

150 Mg(s) + 100 I2(s) → 100 MgI2(s)

I2 is the limiting reactant, and will be completely consumed. There will be consumed 100 Mg atoms. There will remain 50 Mg atoms.

There will be produced 100 MgI2 molecules.

c. 200 atoms of Mg and 300 molecules of I2

We'll have the following equation:

200 Mg(s) + 300 I2(s) →200 MgI2(s)

Mg is the limiting reactant, and will be completely consumed. There will be consumed 200 I2 molecules. There will remain 100 I2 molecules.

There will be produced 200 MgI2 molecules.

d. 0.16 mol Mg and 0.25 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Mg is the limiting reactant, and will be completely consumed. There will be consumed 0.16 mol of I2. There will remain 0.09 mol of I2.

There will be produced 0.16 mol of MgI2.

e. 0.14 mol Mg and 0.14 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

There will be consumed 0.14 mol of Mg and 0.14 mol of I2. there will be produced 0.14 mol of MgI2

f. 0.12 mol Mg and 0.08 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

I2 is the limiting reactant, and will be completely consumed. There will be consumed 0.08 moles of Mg. There will remain 0.04 moles of Mg.

There will be produced 0.08 moles of MgI2.

g. 6.078 g Mg and 63.455 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 6.078 grams / 24.31 g/mol = 0.250 moles

Number of moles I2 = 63.455 grams/ 253.8 g/mol = 0.250 moles

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

There will be consumed 0.250 mol of Mg and 0.250 mol of I2. there will be produced 0.250 mol of MgI2

h. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 2.00 grams/ 253.8 g/mol = 0.00788 moles

I2 is the limiting reactant, and will be completely consumed. There will be consumed 0.00788 moles of Mg. There will remain 0.03322 moles of Mg.

There will be produced 0.00788 moles of MgI2.

i. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 20.00 grams/ 253.8 g/mol = 0.0788 moles

Mg is the limiting reactant, and will be completely consumed. There will be consumed 0.0411 moles of Mg. There will remain 0.0377 moles of I2.

There will be produced 0.0411 moles of MgI2.

4 0

3 years ago

Why would the federal government and city government find it necessary regulate water standard?

Helga [31]

They do this so that when you drink it or use it the contaminates that used to be in it dont make you sick

4 0

3 years ago

2 science questions! 20 POINTS AND WILL REWARD BRAINLIEST!

serious [3.7K]

214, 84 Po ----Beta decay

3 0

3 years ago

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