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Finger [1]
3 years ago
10

A substance that has high reactivity

Chemistry
2 answers:
Fiesta28 [93]3 years ago
5 0
A. easily combines chemically with other substances is your answer.
vichka [17]3 years ago
5 0
A substance that has high reactivity <span>A. easily combines chemically with other substances.</span><span>
</span>
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How many atoms are in c8h8o3?<br> Show your work
Gelneren [198K]

Answer:

im positive that it's 19

8 0
3 years ago
Que enuncia la ley de la conservación de la energia​
Flauer [41]

english:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

spanish:

En física y química, la ley de conservación de la energía establece que la energía total de un sistema aislado permanece constante; se dice que se conserva con el tiempo.

3 0
3 years ago
1. A student attempts to make a saline solution by adding salt to water. How much water did
dexar [7]

111.1 mL of water

Explanation:

Weight per volume concentration (w/v %) is defined as

weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100

volume of solution = (mass of solute × 100) / weight per volume concentration

volume of solution = (1 × 100) / 0.9 = 111.1 mL

volume of water = volume of solution = 111.1 mL

Learn more about:

weight per volume concentration

brainly.com/question/12721794

#learnwithBrainly

8 0
3 years ago
Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 2
IgorC [24]

Answer:

The specific heat of sodium is 1,23J/g°C

Explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

28,2 \frac{J}{mol C} x \frac{1mol}{23g} = 1,23 J/g C

4 0
3 years ago
Determine moles of 1.5g of sodium carbonate.
KIM [24]

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = \frac{1.5}{106}   = 0.014mol

8 0
2 years ago
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