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Nookie1986 [14]
3 years ago
11

What is the value of x in 6 - x/3 = 11 + 2x?

Mathematics
2 answers:
nadya68 [22]3 years ago
3 0
I think that x= -15/7
pav-90 [236]3 years ago
3 0
X= -15/7
negative 15/7
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6 0
2 years ago
Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

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7 0
2 years ago
Subtract.
Rom4ik [11]
(2x + 2) - (3x + 11)
Remove the parentheses
2x + 2 - 3x + 11
And then combine like terms
So the answer is:
-x - 9
7 0
3 years ago
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