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2 years ago

What is released through nuclear fusion in stars? energy gas mass pressure

Physics

2 answers:

trasher [3.6K]2 years ago

7 0

Answer:

Energy is released through nuclear fusion

ohaa [14]2 years ago

6 0

Answer:

A) Energy

Explanation:

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Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy

erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇ + e⁻¹ = ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

= 1.35 MeV

energy of gamma ray photons = .14 + .017

= .157 MeV .

Rest of the energy goes to neutrino .

energy going to neutrino .

= 1.35 - .157

= 1.193 MeV.

5 0

2 years ago

What two major uses does this (H-R)diagram have for astronomers?

EastWind [94]

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7 0

2 years ago

When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and identify which of the foll

goldenfox [79]

Answer:

a) false b) true c) true d) false and e) true

Explanation:

a) false. All the energy applied is used for the phase change, so the temperature remains constant.

b) true. The kinetic energy is associated with the speed of the particles and they have more mobility in the liquid, therefore, more kinetic energy.

c) true. Since energy is used for state change

d) false. In general, mobility and temperature are proportional

e) true. Heat is the source of energy for the change of state

4 0

2 years ago

Read 2 more answers

Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha

ikadub [295]

We have that the spring constant is mathematically given as

$k=2.37*10^{11}N/m$

Generally, the equation for angular velocity is mathematically given by

$\omega=\sqrt{k}{m}$

Where

k=spring constant

And

$\omega =\frac{2\pi}{T}$

Therefore

$\frac{2\pi}{T}=\sqrt{k}{n}$

Hence giving spring constant k

$k=m((\frac{2 \pi}{T})^2$

Generally

Mass of earth $m=5.97*10^{24}$

Period for on complete resolution of Earth around the Sun

$T=365 days$

$T=365*24*3600$

Therefore

$k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2$

$k=2.37*10^{11}N/m$

In conclusion

The effective spring constant of this simple harmonic motion is

$k=2.37*10^{11}N/m$

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3 years ago

A piano mover raises a 1000-n piano at a constant speed using a very light rope in a frictionless pulley system, as shown in the

Rina8888 [55]

Here As we can see the figure that the end of the rope is pulled by some force F

Now as we can see that Piano is connected by a pulley which is passing over the pulley so effectively net force on the piano upwards will be 2F as it is connected by 2 ropes by the pulley

Now for constant velocity of the piano we will say

$2F - mg = ma$

since velocity is constant so acceleration must be ZERO

so here we have

$2F - mg = 0$

as we know here that

mg = 1000 N

so we will have

$2F - 1000 = 0$

$F = 500 N$

so here force must be 500 N

5 0

3 years ago

Read 2 more answers