When a body is moving in circular path at a distance r from its center its velocity at any instant will be directed tangentially. This is what we call tangential velocity. It is calculated as follows:
Vt = r(ω)
where ω = 5 rev/s (2π rad / rev) = 31.42 rad / s
<span>Vt = 0.24(31.42) = 7.5 m/s</span>
I Believe the answer is A but D looks good too.
Answer:
Electric field at a distance of 1.45 cm will be 
Explanation:
We have given the distance d = 1.45 cm = 0.0145 m
And the potential difference 
There is a relation between potential difference and electric field
Electric field at a distance d due to a potential difference is given by
, here E is electric field, V is potential difference and d is distance
So 
Answer:
320N
Explanation:
The magnitude of the torque required is expressed using the formula;
T = Fr sin theta where;
F is the force
r is the radius = 9cm = 0.09m
theta is the angle of inclination = 8 degrees
Torque T = 4Nm
Substitute the given values and get F
4 = F(0.09)sin8
4 = 0.0125F
F = 4/0.0125
F = 320N
Hence the magnitude of the force required when the force is applied at 8 degrees to the wrench is 320N
