Ask question

Ask question

All categories

3 years ago

6

Which utility program reads an assembly language source file and produces an object file?

1 answer:

iragen [17]3 years ago

5 0

Answer:

Assembler

Explanation:

An assembler can be define as a computer utility program that read, interpret and convert software programs written in low level assembly language into an object file, machine language, code and instruction that can be understood and executed by a computer.

You might be interested in

REVIEW QUESTIONS

babunello [35]

Snap rings, and bearings can be used to keep a gear on a shaft, hope this helps!!

5 0

2 years ago

The one end of a hollow square bar whose side is (10+N/100) in with (1+N/100) in thickness is under a tensile stress 102,500 psi

netineya [11]

Answer:

The one end of a hollow square bar whose side is (10+N/100) in wit

Explanation:

3 0

3 years ago

Create a flowchart that describes the following algorithm and then write Python code to implement the algorithm. Write the Pytho

Naya [18.7K]

Answer:

<em>Python code is as follows: </em>

********************************************************************************

#function to get number up to any number of decimal places

def toFixed(value, digits):

return "%.*f" % (digits, value)

print("Enter the price: ", end='', flush=True) #prompt for the input of price

price = float(input()) #taken input

totalCost = price + 0.05 * price #calculating cost

print("Total Cost after the sales tax of 5% is applied: " + toFixed(totalCost,2)) #print and output totalCost

************************************************************************************

3 0

2 years ago

Ô tô có khối lượng m (kg) đặt tại trung tâm h . Khoảng cách từ h tới 2 bánh xe hai bên của a (m) và b (m) , khoảng cách vết bánh

Nutka1998 [239]

Answer:

wiwhwnwhwwbbwbwiwuwhwhehehewhehehheheheehehehehhehehwh

Explanation:

jwhwhwhwhwhwwhhahwhahahwh

6 0

2 years ago

In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W

GrogVix [38]

Answer:

The shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

Explanation:

Given:

Temperature $T = 1273.15$ K

Initial Pressure $P_{1} = 1.8$ MPa

Final pressure $P_{2} = 0.1$ MPa

From the table superheated,

$h_{i} = 4635$ $\frac{K J}{Kg}$ and $h_{f} = 2706.54$ $\frac{K J}{Kg}$

Work done by shaft is,

$W = h_{f} - h_{i}$

$W = 2706.54 - 4635$

$W = -1928.46 \frac{kJ}{kg}$

But here efficiency is 0.56,

So work generated per kg is,

Work = $0.56 \times(- 1928.46)$

Work = $-1.3$ $\frac{MJ}{kg}$

Therefore, the shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

6 0

3 years ago