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3 years ago

Which utility program reads an assembly language source file and produces an object file?

Engineering

1 answer:

iragen [17]3 years ago

5 0

Answer:

Assembler

Explanation:

An assembler can be define as a computer utility program that read, interpret and convert software programs written in low level assembly language into an object file, machine language, code and instruction that can be understood and executed by a computer.

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Answer the following questions in complete sentences. Make sure to explain your thinking.

trapecia [35]

BOY IS IN THE HOOD BOY IS IN THE HOOD

7 0

3 years ago

Consider a thermal energy reservoir at 1500 K that can supply heat at a rate of 150,000 kJ/h. Determine the exergy of this suppl

anzhelika [568]

Answer:

33.4KW

Explanation:

Firstly, we calculate the power index in a reversible heat engine which is given as;

n = 1 - T1/T2

T1 = atmospheric temperature 298k

T2 = reservoir temperature 1500k

n = 1 - 298/1500

n = 0.8013

output energy = n × energy input

0.8013×150000 = 120195KJ/hr

Power output = 120195KJ/hr/3600 = 33.4KW

8 0

3 years ago

Select the correct answer.

irina [24]

The answer is C because the word graphic means picture.

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3 years ago

If you detect that something’s wrong while lowering a lift, you should try to get the vehicle down as fast as possible

Rashid [163]

False, it depends on the situation. If the lift is tilting or anything like I would then get down. Certain training will say to get out and see if you can keep lowering,

4 0

3 years ago

An overhead 25m-long, uninsulated industrial steam pipe of 100-mm diameter, is routed through a building whose walls and air are

wariber [46]

Answer:

1) q=18414.93 W

2) C=12920$

Explanation:

Given data:

pipe length L=25m

pipe diameter D=100mm =0.1 m

air temperature $T_{s1}$ = $T_{\infty1} }$ =25 °C.....= 298.15k

pipe surface temp $T_{s2}$ =150 °C.....=423.15k

surface emissivity e= 0.8

boiler efficiency η=0.90

natural gas price Cg=$0.02 per MJ

1) Total heat loss and radiation heat loss combined

q= $q_{conv} +q_{rad}$

q= $A[h(T_{s2}-T_{s1})+e$ б( $T_{s2}$ ^4- $T_{s1}$ ^4)]....... (1)

б=5.67×10^-8 W/m^2K^4 (boltzmann constant)

area A =L.Dπ=25×0.1π=7.85 m^2

putting all these values in eq (1)

q=18414.93 W

2) suppose boiler is operating non stop annual energy loss will be

E=q.t

=18414.93.3600.24.365

=5.81×10^11 J

to find furnace energy consumption

Ef =E/η

=6.46×10^5 MJ

annual cost

C=Cg. Ef

=12920$

8 0

3 years ago