All categories

3 years ago

Here you go!!!!!!!!!!!!!!!!!1

Engineering

1 answer:

sweet [91]3 years ago

3 0

Answer:

Im confused, what does this mean

Explanation:

i mean, thx lol

You might be interested in

Can someone tell me what car year and model this is please

Arlecino [84]

Answer:

i think 1844

Explanation:

5 0

3 years ago

Read 2 more answers

Think for a moment about the potential problems with big data that the speaker mentioned:

Natalka [10]

Answer: 1. sadly yes, some people are treated unfairly for crimes people yet have commited. 2. no 3. yes

Explanation:

i did this last year

5 0

3 years ago

Read 2 more answers

public interface Frac { /** @return the denominator of this fraction */ int getDenom(); /** @return the numerator of this fracti

True [87]

Answer:

The Full details of the answer is attached.

7 0

3 years ago

An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a speed of 10 ft/s thr

Sladkaya [172]

Answer:

Part A

The mass plow rate, is approximately 97.0 lbm/s

Part B

The power used to overcome friction, is approximately 1.9 hp

Explanation:

The efficiency of the pump, η = 80%

The power input to the pump, P = 20 hp

The speed of the water through the pipe, v = 10 ft./s

The diameter of the pipe, d = 5.2 inches = 13/30 ft.

The free surface of the pool above the lake, h = 80 ft.

The density of the water, ρ = 62.4 lbm/ft.³

Part A

The mass plow rate, $\dot m$ = Q × ρ

Where;

ρ = 62.4 lbm/ft³

Q = A × v

A = The cross-sectional area of the pipe

∴ Q = π·d²/4 × v = π × ((13/30 ft.)²)/4 × 10 ft.s ≈ 1.4748 ft.³/s

∴ The mass plow rate, $\dot m$ ≈ 1.4748 ft.³/s × 62.4 lbm/ft.³ = 97.02752 lbm/s

The mass plow rate, $\dot m$ ≈ 97.0 lbm/s

Part B

The power to pump the water at the given rate, $P_w$ = $\dot m$ ·g·h

∴ $P_w$ = 97.02752 lbm/s × 32.1740 ft./s² × 80 ft. ≈ 14.1130725 Hp

$P_w$ ≈ 14.1130725 Hp

The power output of the pump, $P_{out}$ = 0.8 × 20 hp = 16 hp

Therefore, the power used to overcome friction, $P_f$ = $P_{out}$ - $P_w$

∴ $P_f$ ≈ 16 hp - 14.1130725 Hp ≈ 1.8869275 hp

The power used to overcome friction, $P_f$ ≈ 1.9 hp

7 0

2 years ago

For some metal alloy it is known that the kinetics of recrystallization obey the Avrami equation, and that the value of k in the

JulsSmile [24]

Answer:

t = 1456.8 sec

Explanation:

given data:

contant k = 2.60*10^{-6}

rate of crystallization is 0.0013 s-1

rate of transformation is given by

$r = \frac{1}{t_0.5}$

use specifies value to solve $t_0.5$

it is ime required for 50% tranformation

$r = \frac{1}{.0013}=769.2 sec$

Avrami equation is given by

$y = 1 - e^{-kt^n}$

$0.5 = 1 - e^{-kt_0.5^n}$

$1-0.5 = e^{-kt_0.5^n}$

$ln (1 - 0.5) = -kt_0.5^n$

$ln \frac{ln (1 - 0.5)}{-k} = nln t_0.5$

$n = \frac{ ln \frac{ln (1 - 0.5)}{-k}}{ln t_0.5}$

$n = \frac{ ln \frac{ln (1 - 0.5)}{-2.60*10^{-6}}}{ln 769.2}$

n = 1.88

second degree of recrystalization may be determine by rearranging original avrami equation

$t = [\frac{-ln(1-y)}{k}]^{1/n}$

for 90%completion

$t = [\frac{-ln(1-0.9)}{2.60*10^{-6}}]^{1/1.88}$

t = 1456.8 sec

5 0

3 years ago