Frictional force = vertical force x coeff of friction = 590N x 0.045 = 26.55N
Mass of boy and sled = 590N / g = 590N / 9.8m/s^2 = 60.20 kg
Deceleration due to friction = 26.55N / 60.20kg = 0.44 m/s^2.
For constant acceleration we have:
v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and ti is time. In this case v = 0, u = 5.9 m/s, a = -0.44 m/s^2. So we have
0 = 5.9 - 0.44t
which gives t = 5.9 / 0.44 = 13.409 s.
Distance traveled in this time d = ut + 0.5at^2 = 5.9 x 13.409 - 0.5 x 0.44 x 13.409^2 = 39.56 m
<span>Answer: </span>40 meters
Answer:
Maximum force will be 29040 N
Explanation:
We have given mass of the piston m = 1.5 kg
Amplitude A = 10 cm = 0.1 m
Angular speed 
We know that angular speed is given by 
Squaring both side
k = 290400 N/m
Now force is given by 
The answer is 2 meters per second!
Explanation:
newtons third law of motion says
The average U.S farmer produces enough to feed 150 people
